Ncert Solutions Chemistry Class 11th

$AgC\mathcal{l}+2N{H}_3\to \underset{\left(Solublecomplex\right)}{\left[Ag{\left(N{H}_3\right)}_2\right]C\mathcal{l}}$

Size of hydrated ion $\propto$ $\frac{1}{Ionicmobility}$

Size of hydrated ions $\propto \frac{1}{Ionicsize}$

Size of hydrated ions ; $B{e}^{+2}>M{g}^{+2}>C{a}^{+2}>S{r}^{+2}$

Ionic mobility ; $B{e}^{+2}<M{g}^{+2}<C{a}^{+2}<S{r}^{+2}$

${PV)}_{H_2}={\left(PV\right)}_{Gas}$

${\left(nRT\right)}_{H_2}={\left(nRT\right)}_{Gas}$

$n_{H_2}*T_{H_2}=n_{Gas}*T_{Gas}$

$\Rightarrow \frac{0.2}{2}*200=\frac{3}{{\left(MM\right)}_{Gas}}*300\Rightarrow {\left(MM\right)}_{Gas}=45gm/mole$

To represent in detail NCERT ideas of organic chemistry basics (Class 11, Chapter Organic Chemistry - some basic principles and methodologies), you can use a variety of superb online resources. Sites such as  Khan Academy provide entire notes, video recorded lectures and solved examples which deconstructs hard topics such as nomenclature, isomerism, reaction mechanisms and the effect of electron displacement. Physics Wallah and Aakash also have detailed revision videos as part of the NCERT syllabus which goes into details about these base concepts. Going through the platforms will give you deeper insights than the textbook.

The solution to the Class 11 chemistry chapter 9 exercise can be found on several education sites and that may be on 9 septuplets or 9 Octuplets (either hydrogen or hydrocarbons) depending upon the edition of NCERT syllabus you are following. Some of the best platforms by the likes of Physics Wallah, and Tiwari Academy have complete NCERT solutions that can be found in PDF format or even as a step by step instructions. Video solutions are also provided in the YouTube channels of CBSE Class 11 Chemistry.

CH₄, O₃ & H₂O are green-house gases.

2O₃(g) -> 3O₂

t = 0      a moles               0

-0.5a mole     +0.75a mole

At Eq.    0.5a mole         0.75a mole

Total moles at eq = 0.5a + 0.75 a = 1.25a

$P_{O_3}=x_{O_3}*P_T=\frac{0.5a}{1.25a}*1=\frac{2}{5}atm$

$P_{O_2}=x_{O_2}*p_T=\frac{0.75a}{1.25a}*1=\frac{3}{5}atm$

$K_p=\frac{{\left(P_{O_2}\right)}_{eq}^3}{{\left(P_{O_3}\right)}_{eq}^3}=\frac{{\left(\frac{3}{5}\right)}^3}{{\left(2/5\right)}^2}=1.35atm$

$\Delta G^{°}=-RT\mathcal{l}nKP$

$\begin{array}{l}=-8.3*300\mathcal{l}n1.35\\ =-747J/mole\end{array}$

Phosphorous can expand its covalency beyond 4, as it has vacant 3d orbitals. Nitrogen can't expand its covelency beyond 4, as it does not posses vacant 3d- orbitals.

Fire extinguisher contains sodium Bicarbonate (NaHCO3), also known as baking soda.