Ncert Solutions Chemistry Class 11th

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New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

Degenerate orbitals must have same value of energy

Orbitals with same n and   values are degenerate orbitals.

New answer posted

8 months ago

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A
alok kumar singh

Contributor-Level 10

π = n v R T

π = W M * v R T

5 . 0 3 * 1 0 3 = 2 . 5 M * 0 . 5 * 0 . 0 8 3 * 3 0 0

M = 2 . 5 * 0 . 0 8 3 * 3 0 0 5 . 0 3 * 0 . 5 * 1 0 3 g / m o l

Molar mass of protein, M = 24751 g/mol

 Molar mass of glycine = 75 g/mol

So; number of glycine units =   2 4 7 5 1 7 5 = 3 3 0

New answer posted

8 months ago

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alok kumar singh

Contributor-Level 10

For combustion of Mg:

Mg (s) + 1 2 O 2 ( g ) M g O ( s )

Here,   Δ n g = 1 2

Now using

Δ H = Δ U + Δ n g R T

-601.7 =   Δ U + ( 1 2 ) * 8 . 3 * 1 0 3 * 3 0 0

Δ U = 6 0 0 . 4 5 k J

So; magnitude of   Δ U is 600 kJ (the nearest integer).

New answer posted

8 months ago

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alok kumar singh

Contributor-Level 10

In extraction of copper from copper pyrite (CuFeS2).

FeS converted to FeO as;

2 F e S G a n g u e + 3 O 2 Δ 2 F e O G a n g u e + 2 S O 2          

Then FeO is removed as slag by given reaction

FeO + SiO2 ®   F e S i O 3 S l a g

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8 months ago

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A
alok kumar singh

Contributor-Level 10

Metallic suphides i.e CdS are negatively charged colloidal solution.

Starch colloid is macro molecular colloidal solution.

Fe2O3. xH2O sol is positively charged colloidal solution.

Cheese is an example of gel.

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

? T b = i K b m

? T f = i K f m

? 4 4 = K b * 1 . 5 K f * 4 . 5

K b K f = 3

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

Moles of N2O 2 . 2 4 4 = 1 2 0

Δ H = n C p Δ T = 1 2 0 * 1 0 0 ( 4 0 ) = 2 0 0 J

Δ U = q p + w

w = P e x t . Δ V

w = 1 ( 1 6 7 . 7 5 2 1 7 . 1 ) 1 0 0 0 * 1 0 1 . 3 J = + 5 J

Δ U = 2 0 0 + 5 = 1 9 5 J

New answer posted

8 months ago

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Vishal Baghel

Contributor-Level 10

B a C l 2 + S O 3 2 B a S O 3 W h i t e d i l . H C l S O 2 b u r n i n g s u l p h u r l i k e s m e l l

New answer posted

8 months ago

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Vishal Baghel

Contributor-Level 10

Data is not sufficient but official answer is (D)

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

For 2S, number of radial moles = n l 1 = 2 0 1 = 1  and  Ψ 2 ( r ) will always be positive

o p t i o n ( B ) i s c o r r e c t ?  it has one radial node and it is positive.

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