Ncert Solutions Chemistry Class 11th
Get insights from 2k questions on Ncert Solutions Chemistry Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Ncert Solutions Chemistry Class 11th
- 2k
Questions
- 0
Discussions
- 0
Active Users
- 29
Followers
Have a question about Ncert Solutions Chemistry Class 11th? Ask our experts
Keep it short & simple. Type complete word. Avoid abusive language.
The spontaneity means, having the potential to proceed without the assistance of external agency. The processes which occur spontaneously are (i) flow of heat from colder to warmer body. (ii) Gas in a container contracting into one corner. (iii) Gas expanding to fill the available volume. (iv) Burning carbon in oxygen to give carbon dioxide.
The spontaneity means, having the potential to proceed without the assistance of external agency. The processes which occur spontaneously are (i) flow of heat from colder to warmer body. (ii) Gas in a container contracting into one corner. (iii) Gas expanding to fill the available volume. (iv) Burning carbon in oxygen to give carbon dioxide.
This is a Multiple Choice Questions as classified in NCERT Exemplar
option (iii) and (iv)
Gas expands to fill the available space spontaneously, and burning of carbon to carbon dioxide is spontaneous
Upvote 
In an exothermic reaction, heat is evolved, and system loses heat to the surroundings. For such system
(i) qp will be negative
(ii) ∆rH will be negative
(iii) qp will be positive
(iv) ∆rH will be positive
In an exothermic reaction, heat is evolved, and system loses heat to the surroundings. For such system
(i) qp will be negative
(ii) ∆rH will be negative
(iii) qp will be positive
(iv) ∆rH will be positive
This is a Multiple Choice Questions as classified in NCERT Exemplar
option (i) and (ii)
In an exothermic reaction, heat is evolved, and system loses heat to the surroundings. Therefore, qp will be negative and? rH will also be negative. Hence, option (i) and (ii) is the correct answer.
Upvote Thermodynamics mainly deals with
(i) Interrelation of various forms of energy and their transformation from one form to another.
(ii) Energy changes in the processes which depend only on initial and final states of the microscopic systems containing a few molecules.
(iii) How and at what rate these energy transformations are carried out.
(iv) The system in equilibrium state or moving from one equilibrium state to another equilibrium state.
Thermodynamics mainly deals with
(i) Interrelation of various forms of energy and their transformation from one form to another.
(ii) Energy changes in the processes which depend only on initial and final states of the microscopic systems containing a few molecules.
(iii) How and at what rate these energy transformations are carried out.
(iv) The system in equilibrium state or moving from one equilibrium state to another equilibrium state.
This is a Multiple Choice Questions as classified in NCERT Exemplar
option (i)
The laws of thermodynamics deal with energy changes of macroscopic systems involving a large number of molecules rather than microscopic systems containing a few molecules. Laws of thermodynamics apply only when a system is
Upvote Which of the following is not correct?
(i) ∆G is zero for a reversible reaction
(ii) ∆G is positive for a spontaneous reaction
(iii) ∆G is negative for a spontaneous reaction
(iv) ∆G is positive for a non-spontaneous reaction
Which of the following is not correct?
(i) ∆G is zero for a reversible reaction
(ii) ∆G is positive for a spontaneous reaction
(iii) ∆G is negative for a spontaneous reaction
(iv) ∆G is positive for a non-spontaneous reaction
This is a Multiple Choice Questions as classified in NCERT Exemplar
option (ii)
positive for a spontaneous reaction
Upvote Enthalpy of sublimation of a substance is equal to
(i) Enthalpy of fusion + enthalpy of vapourisation
(ii) Enthalpy of fusion
(iii) Enthalpy of vapourisation
(iv) Twice the enthalpy of vapourisation
Enthalpy of sublimation of a substance is equal to
(i) Enthalpy of fusion + enthalpy of vapourisation
(ii) Enthalpy of fusion
(iii) Enthalpy of vapourisation
(iv) Twice the enthalpy of vapourisation
This is a Multiple Choice Questions as classified in NCERT Exemplar
Option (i)
Enthalpy of sublimation can be shown as
Solid | Liquid | Vapour
Hence, Enthalpy of sublimation of a substance is equal to enthalpy of fusion + enthalpy of vaporisation.
Upvote The enthalpies of elements in their standard states are taken as zero. The enthalpy of formation of a compound
(i) Is always negative
(ii) Is always positive
(iii) May be positive or negative
(iv) Is never negative
The enthalpies of elements in their standard states are taken as zero. The enthalpy of formation of a compound
(i) Is always negative
(ii) Is always positive
(iii) May be positive or negative
(iv) Is never negative
This is a Multiple Choice Questions as classified in NCERT Exemplar
option (iii)
The enthalpies of elements in their standard states are taken as zero. The enthalpy of formation of a compound as the reaction could be exothermic or endothermic.
Upvote Consider the reactions given below. On the basis of these reactions find out which of the algebric relations given in options (i) to (iv) is correct?
(a) C (g) + 4H (g) → CH4 (g); ∆r H = x kJ/ mol
(b) C (graphite,s) + 2H2 (g) → CH4 (g); ∆rH = y kJ /mol
(i) x = y
(ii) x = 2y
(iii) x > y
(iv) x < y
Consider the reactions given below. On the basis of these reactions find out which of the algebric relations given in options (i) to (iv) is correct?
(a) C (g) + 4H (g) → CH4 (g); ∆r H = x kJ/ mol
(b) C (graphite,s) + 2H2 (g) → CH4 (g); ∆rH = y kJ /mol
(i) x = y
(ii) x = 2y
(iii) x > y
(iv) x < y
This is a Multiple Choice Questions as classified in NCERT Exemplar
option (iii)
Same bonds are formed in reaction (a) and (b) but bonds between the reactant molecules are broken only in reaction (b)
Upvote On the basis of thermochemical equations (a), (b) and (c), find out which of the algebric relationships given in options (i) to (iv) is correct.
(a) C (graphite) + O2 (g) → CO2 (g) ; ∆rH = x kJ/ mol
(b) C (graphite) + O2 (g) → CO (g) ; ∆rH = y kJ/ mol
(c) CO (g) + O2 (g) → CO2 (g) ; ∆rH = z kJ/ mol
(i) z = x + y
(ii) x = y – z
(iii) x = y + z
(iv) y = 2z – x
On the basis of thermochemical equations (a), (b) and (c), find out which of the algebric relationships given in options (i) to (iv) is correct.
(a) C (graphite) + O2 (g) → CO2 (g) ; ∆rH = x kJ/ mol
(b) C (graphite) + O2 (g) → CO (g) ; ∆rH = y kJ/ mol
(c) CO (g) + O2 (g) → CO2 (g) ; ∆rH = z kJ/ mol
(i) z = x + y
(ii) x = y – z
(iii) x = y + z
(iv) y = 2z – x
This is a Multiple Choice Questions as classified in NCERT Exemplar
option (iii)
When we add equations (b) and (c) we will get equation (a); hence, the Algebraic sum of y and z will give x, x =y + z.
Upvote Assertion (A): Among isomeric pentanes, 2, 2-dimethylpentane has highest boiling point.
Reason (R): Branching does not affect the boiling point.
(i) Both A and R are correct and R is the correct explanation of A.
(ii) Both A and R are correct but R is not the correct explanation of A.
(iii) Both A and R are not correct.
(iv) A is not correct but R is correct.
Assertion (A): Among isomeric pentanes, 2, 2-dimethylpentane has highest boiling point.
Reason (R): Branching does not affect the boiling point.
(i) Both A and R are correct and R is the correct explanation of A.
(ii) Both A and R are correct but R is not the correct explanation of A.
(iii) Both A and R are not correct.
(iv) A is not correct but R is correct.
This is a assertion and reason answer type question as classified in NCERT Exemplar
(iii) With the branching the boiling decreases due to the decrease in surface area which leads to decrease its van there Waals force.
Upvote The entropy change can be calculated by using the expression ∆S = . When water freezes in a glass beaker, choose the correct statement amongst the following:
(i) ∆S (system) decreases, but ∆S (surroundings) remains the same.
(ii) ∆S (system) increases, but ∆S (surroundings) decreases.
(iii) ∆S (system) decreases, but ∆S (surroundings) increases.
(iv) ∆S (system) decreases, and ∆S (surroundings) also decreases.
The entropy change can be calculated by using the expression ∆S = . When water freezes in a glass beaker, choose the correct statement amongst the following:
(i) ∆S (system) decreases, but ∆S (surroundings) remains the same.
(ii) ∆S (system) increases, but ∆S (surroundings) decreases.
(iii) ∆S (system) decreases, but ∆S (surroundings) increases.
(iv) ∆S (system) decreases, and ∆S (surroundings) also decreases.
This is a Multiple Choice Questions as classified in NCERT Exemplar
option (iii)? S (system) decreases, but? S (surroundings) increases.
Upvote