Ncert Solutions Chemistry Class 11th

In an adiabatic process, no transfer of heat takes place between system and surroundings. Choose the correct option for free expansion of an ideal gas under adiabatic condition from the following.

(i) q = 0, ∆T ≠ 0, w = 0

(ii) q ≠ 0, ∆T = 0, w = 0

(iii) q = 0, ∆T = 0, w = 0

(iv) q = 0, ∆T < 0, w 0 V_f

Assertion (A): Toluene on Friedal Crafts methylation gives o– and p–xylene. 

Reason (R): CH₃-group bonded to benzene ring increases electron density at o– and p– position. 

(i) Both A and R are correct and R is the correct explanation of A. 

(ii) Both A and R are correct but R is not the correct explanation of A. 

(iii) Both A and R are not correct. 

(iv) A is not correct but R is correct.

It is cyclic and has conjugated 8π-electron system but it is not an aromatic compound.

Reason (R) : (4n + 2) π electrons rule does not hold good and ring is not planar.

(i) Both A and R are correct and R is the correct explanation of A.

(ii) Both A and R are correct but R is not the correct explanation of A.

(iii) Both A and R are not correct.

(iv) A is not correct but R is correct.

Match the reactions given in Column I with the reaction types in Column II.

Match the following reactants in Column I with the corresponding reaction products in Column II.

∆_fU $°$ of formation of CH₄ (g) at certain temperature is –393 kJ/mol. The value of ∆_fH $°$ is

(i) zero

(ii) < _f U $°$

(iii) > ∆_f U $°$

(iv) Equal to ∆_fU $°$

Match the hydrocarbons in Column I with the boiling points given in Column II.

During complete combustion of one mole of butane, 2658 kJ of heat is released. The thermochemical reaction for above change is

(i) 2C₄H₁₀(g) + 13O₂(g) → 8CO₂(g) + 10H₂O(l) ∆_c H = –2658.0 kJ/mol

(ii) C₄H₁₀(g) $\frac{13}{2}$ +  O₂ (g) → 4CO₂ (g) + 5H₂O (g) ∆_c H = –1329.0 kJ/mol

(iii) C₄H₁₀(g) $\frac{13}{2}$ +  O₂ (g) → 4CO₂ (g) + 5H₂O (l) ∆_c H = –2658.0 kJ/mol

(iv) C₄H₁₀ (g) $\frac{13}{2}$ + O₂ (g) → 4CO₂ (g) + 5H₂O (l) ∆_c H = +2658.0 kJ/mol

Match the reagent from Column I which on reaction with 

CH₃ – CH=CH₂ gives some product given in Column II as per the codes given below:

The molecules having dipole moment are __________. 

(i) 2,2-Dimethylpropane 

(ii) Trans-Pent-2-ene 

(iii) Cis-Hex-3-ene 

(iv) 2, 2, 3, 3 - Tetramethylbutane.