Ncert Solutions Chemistry Class 11th
Get insights from 2k questions on Ncert Solutions Chemistry Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Ncert Solutions Chemistry Class 11th
- 2k
Questions
- 0
Discussions
- 0
Active Users
- 29
Followers
Have a question about Ncert Solutions Chemistry Class 11th? Ask our experts
Keep it short & simple. Type complete word. Avoid abusive language.
An alkane C8H18 is obtained as the only product on subjecting a primary alkyl halide to Wurtz reaction. On monobromination this alkane yields a single isomer of a tertiary bromide. Write the structure of alkane and the tertiary bromide.
An alkane C8H18 is obtained as the only product on subjecting a primary alkyl halide to Wurtz reaction. On monobromination this alkane yields a single isomer of a tertiary bromide. Write the structure of alkane and the tertiary bromide.
This is a short answer type question as classified in NCERT Exemplar
The reaction is
The alkane is
The tertiary bromide is
Upvote 
Which one of the following statements is correct?
(a) Fe3+ is more paramagnetic than Fe2+.
(b) Fe2+ is more paramagnetic than Fe3+.
(c) Both are equally paramagnetic.
(d) They are non-magnetic.
Which one of the following statements is correct?
(a) Fe3+ is more paramagnetic than Fe2+.
(b) Fe2+ is more paramagnetic than Fe3+.
(c) Both are equally paramagnetic.
(d) They are non-magnetic.
(a) As Fe3+ contains 5 impaired electrons while Fe2+ contains only 4 unpaired electrons. Fe3+ is more paramagnetic.
Upvote Write hydrocarbon radicals that can be formed as intermediates during monochlorination of 2-methylpropane? Which of them is more stable? Give reasons
Write hydrocarbon radicals that can be formed as intermediates during monochlorination of 2-methylpropane? Which of them is more stable? Give reasons
This is a short answer type question as classified in NCERT Exemplar
The 2-methylpropane would lead to two types of radicals.
Among the two 3o radical is most stable as it contains 9 ∝ -hydrogen whereas 1o radical contains only 1 ∝ -hydrogen.
Upvote Assertion: Symmetrical distribution of electrons leads to stability.
Reason: Electronic distribution of an element is important to understand and explain the chemical behaviour of the element.
Assertion: Symmetrical distribution of electrons leads to stability.
Reason: Electronic distribution of an element is important to understand and explain the chemical behaviour of the element.
(b) Both the statements are correct but R is not the reason for A.
Upvote Assertion: Chromium and copper have five and ten electrons in 3d orbitals rather than four and nine as their position would have indicated with two-electrons in the 4s orbital.
Reason: Fully filled and half-filled orbital shave extra stability that is, lower energy.
Assertion: Chromium and copper have five and ten electrons in 3d orbitals rather than four and nine as their position would have indicated with two-electrons in the 4s orbital.
Reason: Fully filled and half-filled orbital shave extra stability that is, lower energy.
(a) Fully filled and half-filled orbitals have extra stability (that is, lower energy). Thus, p3, p6, d5, d10, f 7, f14 etc. configurations, which are either half-filled or filled, are more stable. Chromium and copper therefore adopt the d5 and d10 configuration.
Upvote Write the structures and names of products obtained in the reactions of sodium with a mixture of 1-iodo-2-methylpropane and 2-iodopropane.
Write the structures and names of products obtained in the reactions of sodium with a mixture of 1-iodo-2-methylpropane and 2-iodopropane.
This is a short answer type question as classified in NCERT Exemplar
It is a Wurtz reaction where alkane is formed.
Upvote Assertion: Both the exact position and exact velocity of an electron in an atom cannot be determined simultaneously (Heisenberg uncertainty principle).
Reason: The path of an electron in an atom can be determined accurately.
Assertion: Both the exact position and exact velocity of an electron in an atom cannot be determined simultaneously (Heisenberg uncertainty principle).
Reason: The path of an electron in an atom can be determined accurately.
(c) The path of an electron in an atom can never be determined or known accurately. That is why there is only a probability of finding the electron at different points in an atom.
Upvote The relative reactivity of 1°, 2°, 3° hydrogen’s towards chlorination is 1 : 3.8 : 5. Calculate the percentages of all monochlorinated products obtained from 2-methylbutane.
The relative reactivity of 1°, 2°, 3° hydrogen’s towards chlorination is 1 : 3.8 : 5. Calculate the percentages of all monochlorinated products obtained from 2-methylbutane.
This is a short answer type question as classified in NCERT Exemplar
The structure of 2-methylbutane is
2-methylbutane
Total number | Total amount of monochlorinated Product | % of monochlorinated product | |
1° | 9 | 9 | 41.7 |
2° | 2 | 7.6 | 35.2 |
3° | 1 | 5 | 23.1 |
Upvote Assertion: Classical mechanics fails when applied to microscopic objects like electrons, atoms, molecules etc.
Reason: Classical mechanics ignores the concept of dual behaviour of matter especially for sub-atomic particles and the uncertainty principle.
Assertion: Classical mechanics fails when applied to microscopic objects like electrons, atoms, molecules etc.
Reason: Classical mechanics ignores the concept of dual behaviour of matter especially for sub-atomic particles and the uncertainty principle.
(a) Classical mechanics applies to the macro world and hence fails when it is applied to the micro world. In the micro world, quantum mechanics incorporates all the principles like the uncertainty principle, dual behaviour etc.
Upvote