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(a) For n = 4, No. of sub-shells = (l = 0, l = 1, l = 2, l = 3) = 4.
(b) Total number of orbitals which can be present = n2 = 42 = 16. Each orbital can have an electron with ms = – 1/2. Total no. of electrons with m, = – 1/2 is 16.
Si (Z = 14): [Ne]103s23p2 The unpaired electrons in silicon (Si) will experience more effective nuclear charge because the atomic number of the element Si is more than that of Al.
Greater the penetration of the electron present in a particular orbital towards the nucleus more will be the magnitude of the effective nuclear charge. Based upon this
(i) 2s orbital is closer to the nucleus than 3s orbital and hence it will experience more effective nuclear charge.
The nuclear charge experienced by electrons depends on the distance between the nucleus and orbital. The greater is this distance, the lesser is the effective nuclear charge. Among all the p orbitals, 4p orbital lies the farthest from the nucleus and thus experiences the lowest effective nuclear ch