Ncert Solutions Chemistry Class 12th
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7 months agoContributor-Level 9
A 6.5 molal solution means 6.5 moles of KOH is in 1 kg (1000 g) of solvent (H? O).
Moles of solute, n_B = 6.5
Mass of solute, W_B = 6.5 * 56 = 364 g
Mass of solvent, W_A = 1000 g
Mass of solution = 1364 g
Volume of solution = 1364 / 1.89 mL
Now, molarity = [6.5 / (1364 / 1.89)] * 1000 M = 9 M
New answer posted
7 months agoContributor-Level 9
Solubility product of A? X = 4S? ³
Where S? is the solubility of salt A? X.
Solubility product of MX = S? ²
Where S? is the solubility of MX.
Given 4S? ³ = 4 * 10? ¹² ⇒ S? = 10? M
Given S? ² = 4 * 10? ¹² ⇒ S? = 2 * 10? M
So, S? / S? = 10? / (2 * 10? ) = 50
New answer posted
7 months agoContributor-Level 9
Edge length in bcc, a? = 27 Å
Let, Edge length in fcc be a? Å
Now, the same element crystallises in bcc as well as fcc.
For bcc: 4r = √3 a? ⇒ r = (√3 / 4) a?
For fcc: 4r = √2 a? ⇒ r = a? / (2√2)
So, (√3 / 4) a? = a? / (2√2)
(√3 / 4) * 27 = a? / (2√2)
a? = 33.13 Å
The nearest integer is 33.
New answer posted
7 months agoContributor-Level 9
Roasting is a process in which sulphur is removed as SO? gas from sulphide ores on heating in excess of oxygen.
New answer posted
7 months ago
Contributor-Level 9
R-CONH? + Br? + 4NaOH → R-NH? + 2NaBr + Na? CO? + 2H? O
This reaction is the Hoffmann bromamide degradation, in which an amide is converted to a 1° amine.
New answer posted
7 months agoContributor-Level 9
The E° value for Ce? /Ce³? is +1.74 V, which suggests that Ce? is a strong oxidant, reverting to its common +3 oxidation state. So, Ce³? is more stable than Ce?
New answer posted
7 months agoContributor-Level 9
The size of the Bk³? ion is less than the Np³? ion because Berkelium (Bk) lies beyond Neptunium (Np) in the actinoid series, and the size variation here is because of the actinoid contraction.
New answer posted
7 months agoContributor-Level 9
The enol form of acetone exists in less than 0.1% quantity, since its keto form is highly stable. But in the case of acetylacetone, the enol form is stabilized by intramolecular H-bonding, so its quantity increases to approximately 15%.
The intramolecular H-bond in the enol form of acetylacetone is shown.
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