Ncert Solutions Chemistry Class 12th
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2 months agoContributor-Level 10
Λ°m (NaCl) = 126.45Scm² mol? ¹
Λ°m (HCl) = 426.16Scm² mol? ¹
Λ°m (CH? COONa) = 91Scm² mol? ¹
Λ°m (CH? COOH) =Λ°m (CH? COONa) +Λ°m (HCl)−Λ°m (NaCl)
= 91 + 426.16 – 126.45
= 391.72Scm² mol? ¹
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2 months agoNew answer posted
2 months agoContributor-Level 10
Vitamin B? deficiency → Pernicious anaemia (RBC deficient in heamoglobin)
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2 months agoContributor-Level 10
The IUPAC name giving the lowest number to the functional group obeying the lowest set of locants is 1-bromo-5-chloro-4-methylhexan-3-ol.
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2 months agoNew answer posted
2 months agoContributor-Level 10
Oxidation state in neutral medium changes from +7 to +4 for MnO? to MnO?
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2 months agoContributor-Level 10
Statement I is true but statement II is incorrect as 3°-alcohols are the most reactive and give immediate turbidity with Luca's reagent.
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2 months agoContributor-Level 10
Hematite: Fe? O?
Magnetite: Fe? O?
Calamine: ZnCO?
Kaolinite: [Al? (OH)? Si? O? ]
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2 months agoContributor-Level 10
kc = [O? ]² / [O? ]³
3 * 10? = [O? ]² / [4 * 10? ²]³
[O? ]² = 192 * 10? ⇒ [O? ] = 4.38 * 10? ³²
New answer posted
2 months agoContributor-Level 10
When acetone & 2-pentanone are added in a base for an aldol condensation reaction there are several possibilities that may arise for product formation.
But structure in choice (2) is not possible. It will be possible with 3-pentanone.
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