Probability
Get insights from 304 questions on Probability, answered by students, alumni, and experts. You may also ask and answer any question you like about Probability
- 304
Questions
- 0
Discussions
- 0
Active Users
- 4
Followers
Have a question about Probability? Ask our experts
Keep it short & simple. Type complete word. Avoid abusive language.
What are real world examples of the probability in Maths.
What are real world examples of the probability in Maths.
The examples of the probability include - flipping a coin, rolling a die, drawing a card from a deck, and picking a ball from a bag.
According to Class 11 Maths, which are the applications of the probability?
According to Class 11 Maths, which are the applications of the probability?
There are various applications of the probability in the real life. It is used to take informed decisions and risks in the following areas - insurance, weather forecasting, finance, business, sports, computer Science and gaming.
What are the basic rules of Probability in Class 11 Maths?
What are the basic rules of Probability in Class 11 Maths?
There are two basic rules for finding the Probability of two events A and B - Multiplication Rule and Addition Rule.
According to Class 11 Maths, what are the types of probability.
According to Class 11 Maths, what are the types of probability.
There are four types of probability - Classical, Empirical, Subjective, and Axiomatic Probability. The classical probability is based on the logical and known outcomes, Empirical are based on data from actual experiments, and subjective is based on intuition, personal opinion, or experience.
Probability in Maths is used to calculate how an event is likely to occur. It is measured by dividing the favorable outcomes number by the number of possible outcomes. It is expressed from 0% to 100% or by either 0 (impossible) or 1 (certain).
From first 100 natural numbers, 3 numbers are selected. If these numbers are in A.P., then the probability that these numbers are even is:
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
From first 100 natural numbers, 3 numbers are selected. If these numbers are in A.P., then the probability that these numbers are even is:
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
A: 3 numbers are in A.P.
B: 3 numbers are even
P (B/A) = n (A ∩ B) / n (A) = (²? C? + ²? C? ) / (? C? +? C? ) = (25 × 24) / (50 × 49) = 12/49
There are 5 identical red balls and 3 identical yellow balls in a box. Two balls are drawn at random, then the probability that their colour is different is
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
There are 5 identical red balls and 3 identical yellow balls in a box. Two balls are drawn at random, then the probability that their colour is different is
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
5 red, 3 yellow
There are 3 points in sample space either both are red or both are yellow or one is red other is yellow.
⇒ P (E) = (3.5+5.3) / (3.5+5.3+5.4+3.2) = 15/28
The mean age of 25 teachers in a school is 40 years. A teacher retires at the age of 60 years and a new teacher is appointed in his place. If the mean age of the teachers in this school now is 39 years, then the age (in years) of the newly appointed teacher is: ______.
The mean age of 25 teachers in a school is 40 years. A teacher retires at the age of 60 years and a new teacher is appointed in his place. If the mean age of the teachers in this school now is 39 years, then the age (in years) of the newly appointed teacher is: ______.
Initial mean of 25 observations is 40.
X? = (Σx? )/25 = 40 => Σx? = 25 * 40 = 1000.
A teacher of age 60 retires.
The new sum of ages for the remaining 24 people is 1000 - 60 = 940.
A new teacher of age x joins.
The new sum for 25 people is 940 + x.
The new mean is 39.
(940 + x) / 25 = 39
940 + x = 39 * 25
Two dices are rolled. If both dices have six faces numbered 1,2,3,5,7 and 11, then the probability that the sum of the numbers on the top faces is less than or equal to 8 is:
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
Two dices are rolled. If both dices have six faces numbered 1,2,3,5,7 and 11, then the probability that the sum of the numbers on the top faces is less than or equal to 8 is:
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
n (s) = 6² = 36
E = { (1, 1), (1, 2), (1, 3), (1, 5), (1, 7), (2, 1), (2, 2), (2, 3), (2, 5), (3, 1), (3, 2), (3, 3), (3, 5), (5, 1), (5, 2), (5, 3), (7, 1)}
∴ n (E) = 17
Required prob. = n (E) / n (S) = 17 / 36
Related Tags
0 Followers
0 Followers
0 Followers
0 Followers
0 Followers
0 Followers
0 Followers
0 Followers
0 Followers
0 Followers