Chemistry NCERT Exemplar Solutions Class 12th Chapter Thirteen

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Vishal Baghel

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This is a Short Type Questions as classified in NCERT Exemplar

 

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Vishal Baghel

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This is a Short Type Questions as classified in NCERT Exemplar

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Vishal Baghel

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This is a Short Type Questions as classified in NCERT Exemplar

Ans: On reaction with hydrochloric acid, aniline forms anilinium chloride ion which is water soluble. Therefore, the aniline solubility in aqueous HCl solution. 

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Ans: Carbylamine reaction is shown by primary amines only, primary amines react with chloroform in the presence of alcoholic KOH to form isocyanides which upon catalytic reduction gives secondary amines as the final product. 

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Ans: Z is an aliphatic amine that produces a solid that is insoluble in base. This means that the reaction with C6H5SO2Cl must produce a product with no replaceable hydrogen attached to nitrogen.

To put it another way, the amine must be a secondary amine.

Z stands for ethylmethylamine.

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Ans: N, N-dimethylbenzenanmine 

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Ans:  CH3CH2CH3 < CH3CH2NH2 < CH3CH2OH

As oxygen is more electronegative than nitrogen therefore, the O-H bond is more polar than the N-H bond. So ethanol has more dipole moments than ethylamine. Propane is non- polar in nature hence, had the least among all. 

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Ans: CS2 is a non-polar solvent which decreases the activating effect of? NH2. As a result, mono substitution occurs only at o- and p- positions giving a mixture of 2-bromoaniline (minor) and 4-bromoaniline (major) as products. 

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Ans: The azo products have an extended conjugate system with both aromatic rings linked by the –N=N- bond. These compounds are frequently colored and used as dyes. Benzene diazonium chloride reacts with phenol to form p-hydroxy azobenzene by coupling the phenol molecule in its para position with the diazonium salt. This is referred to as a coupling reaction.

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