Chemistry
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New answer posted
a year agoContributor-Level 10
This problem involves the stoichiometry of acid-base neutralization.
o For the reaction with H? PO? (a dibasic acid), 100 mL of NaOH is required.
o For the reaction with H? PO? (a monobasic acid), 200 mL of NaOH is required.
New answer posted
a year agoContributor-Level 10
In proteins, the secondary structure (such as α-helices and β-sheets) is stabilized by hydrogen bonds formed between the carbonyl oxygen of one peptide bond and the amide hydrogen of another.
New answer posted
a year agoContributor-Level 10
The magnetic moment of an ion is determined by its number of unpaired electrons (n). For the given lanthanide ions:
o Ce? has 0 unpaired electrons (4f? ).
o Eu³? has 6 unpaired electrons (4f? ).
o Gd³? has 7 unpaired electrons (4f? ).
Gd³? has the highest number of unpaired electrons and therefore the highest magnetic moment.
New answer posted
a year ago
Contributor-Level 10
The Lassaign's test is a qualitative analysis method used to detect nitrogen, sulfur, phosphorus, and halogens in an organic compound. Copper (II) oxide is used to detect carbon. In the sodium fusion extract, halides (X? ) precipitate with AgNO? , and sulfide (S²? ) precipitates as black PbS.
New answer posted
a year agoContributor-Level 9
Solubility of CdSO? is water ; S = 8 * 10? M
Using Ksp = S²
Ksp = 64 * 10? M
Now,
CdSO? Cd²? + SO? ²?
in H? SO? (0.01M)
Ksp = [Cd²? ] [SO? ²? ]
64 * 10? = S? (S? + 0.01)
S? << 0.01
So, S? = 64 * 10? M.
New answer posted
a year agoContributor-Level 9
ΔG° = + 25.2 kJ / mol
Using ΔG° = -2.3 RT log Kp
25.2 * 10³ = - 2.3 * 8.3 * 400 log Kp
o 3.3 = log Kp
log (1 / 2*10³) = log Kp
Kp = 1 / (2*10³)
Using; Kp = Kc (RT)
1 / (2*10³) = Kc (0.083 * 400)? ¹
New answer posted
a year ago
Contributor-Level 9
Moles of benzoic acid = 6.1 / 121 = 0.05
Theoretical moles of m- bromobenzoic acid = 0.05
Observed moles of m- bromobenzoic acid = 7.8 / 200 = 0.039
% yield = (0.039 / 0.05) * 100 = 78%
New answer posted
a year agoContributor-Level 9
Half life, t? /? = 1min
Let, time of 99.9% completion of reaction be 't' min
Let the reaction is of first order
K = (2.303/t) log? ( [R]? / [R])
[R] = 0.001 [R]?
t = (2.303 * 3 min) / 0.693
t = 9.99 min
the nearest integer is 10.
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