Chemistry

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New answer posted

3 months ago

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R
Raj Pandey

Contributor-Level 9

In Tollen's test for aldehyde, aldehyde is oxidized to carboxylic acid salt as:
R – CHO + H? O →R – COO? + 3H? + 2e?
So; 2e? are transferred per aldhyde group.

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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3 months ago

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R
Raj Pandey

Contributor-Level 9

Partial hydrolysis of XeF? gives XeO? F?
XeF? + 2H? O → XeO? F? + 4HF
Compound A is XeF? , so number of lone pair on Xe is 1.

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3 months ago

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R
Raj Pandey

Contributor-Level 9

ClF? and XeF? have two lone pairs of electrons on central atom.

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alok kumar singh

Contributor-Level 10

The reduction of aluminum oxide (Al? O? ) is performed through an electrolytic process in its molten state. This method is necessary because Al? O? is a highly ionic and stable compound.

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3 months ago

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Raj Pandey

Contributor-Level 9

m=2 molal
ΔT? = 100.52 – 100 = 0.52°C
Using, ΔT? = iK? m
0.52 = I * 0.52 * 2
i = 0.5
Now using, α = (1-i) / (1-1/n)
Where, n=2 (dimerisation)
α = (1-0.5) / (1-0.5) = 1
So, percentage association = 100%

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3 months ago

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alok kumar singh

Contributor-Level 10

In a C? fullerene molecule, all 60 carbon atoms are identical. Each carbon atom is bonded to three other carbon atoms via sigma bonds. The structure is composed of 20 six-membered rings and 12 five-membered rings.

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3 months ago

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alok kumar singh

Contributor-Level 10

In diacetamide (CH? CO)? NH), the lone pair of electrons on the nitrogen atom is delocalized through resonance with both adjacent carbonyl groups. This extensive resonance greatly decreases the electron density on the nitrogen atom.

New answer posted

3 months ago

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

The difference between the first and second ionization energies is significantly higher for alkali metals (like Sodium, Na) compared to alkaline earth metals (like Magnesium, Mg). Therefore, in the context of the problem, X=Na and Y=Mg.

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