Chemistry
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New answer posted
7 months agoContributor-Level 10
Hormones present in the human body are:
- Thyrotropin-releasing hormone (TRH)
Dopamine (prolactin-inhibiting hormones)
Gonadotropin-releasing hormone (GnRH)
Adrenal Glands
Androgens
Estrogen
Inhibin
Testosterone
Gastrin
Melatonin
New answer posted
7 months agoContributor-Level 10
Below is the list of hormones:
- Cortisol
- Estrogen & Progesterone
- Aldosterone
- Insulin
- Growth Hormone
- Glucagon
- Adrenaline (Epinephrine)
- Thyroxine (T4) and Triiodothyronine (T3)
- Melatonin
New answer posted
7 months agoContributor-Level 10
There are multiple factors that make the carbonyl group a strong ligand. Check the list below for the reasons.
- Unlike other alkyl ligands, it is an unsaturated compound.
- Due to its unsaturated nature, it has difficulty donating? electron density.
- It has a tendency to accept? (Pie) antibonding electrons.
- CO ligand acts as Lewis acid and donates a lone pair of electrons to form a metal-carbon bond.
- The? -acidic nature of CO gives a strong field and greater d-orbital splitting.
New answer posted
7 months agoContributor-Level 10
To understand the phenomenon behind this, have a close look at the formula of the first order reaction.
t1/2 = 0.693/k
Here, we can see that the half life is only dependent on k (rate constant) since there is no [A]' in the formula. Hence, we can easily conclude that the half life of a first order reaction is independent of the initial concentration [A]'.
New answer posted
7 months agoContributor-Level 10
log (k? /k? ) = (Ea / 2.303R) [1/T? - 1/T? ]
log (3.555) = (Ea / (2.303R) [1/303 - 1/313]
1.268 * 8.314 * 303 * 313 = 10Ea
So, Ea = 100 kJ
New answer posted
7 months agoContributor-Level 10
According to IUPAC convention for naming of elements with atomic number more than 100, different digits are written in order and at the end ium is added. For digits following naming is used.
0 -nil
1-un
2-bi
3-tri
and so on.
New answer posted
7 months agoContributor-Level 10
(x/m) = k (P)¹/?
log (x/m) = log k + (1/n) log P
Slope = 1/n = 2 So n = ½
Intercept ⇒ log k = 0.477 So k = Antilog (0.477) = 3
So (x/m) = k (P)¹/? = 3 [0.04]² = 48 * 10?
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