Chemistry

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New answer posted

7 months ago

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V
Vikash Kumar Vishwakarma

Contributor-Level 10

Hormones present in the human body are:

  • Thyrotropin-releasing hormone (TRH)
  • Dopamine (prolactin-inhibiting hormones)

  • Gonadotropin-releasing hormone (GnRH)

  • Adrenal Glands

  • Androgens

  • Estrogen

  • Inhibin

  • Testosterone

  • Gastrin

  • Melatonin

New answer posted

7 months ago

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V
Vikash Kumar Vishwakarma

Contributor-Level 10

Below is the list of hormones:

  1. Cortisol
  2. Estrogen & Progesterone
  3. Aldosterone 
  4. Insulin
  5. Growth Hormone
  6. Glucagon
  7. Adrenaline (Epinephrine)
  8. Thyroxine (T4) and Triiodothyronine (T3)
  9. Melatonin

New answer posted

7 months ago

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N
nitesh singh

Contributor-Level 10

There are multiple factors that make the carbonyl group a strong ligand. Check the list below for the reasons.

  • Unlike other alkyl ligands, it is an unsaturated compound.
  • Due to its unsaturated nature, it has difficulty donating? electron density.
  • It has a tendency to accept? (Pie) antibonding electrons.
  • CO ligand acts as Lewis acid and donates a lone pair of electrons to form a metal-carbon bond.
  • The? -acidic nature of CO gives a strong field and greater d-orbital splitting.

New answer posted

7 months ago

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A
Aadit Singh Uppal

Contributor-Level 10

To understand the phenomenon behind this, have a close look at the formula of the first order reaction.

t1/2 = 0.693/k

Here, we can see that the half life is only dependent on k (rate constant) since there is no [A]' in the formula. Hence, we can easily conclude that the half life of a first order reaction is independent of the initial concentration [A]'.

New answer posted

7 months ago

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A
alok kumar singh

Contributor-Level 10

log (k? /k? ) = (Ea / 2.303R) [1/T? - 1/T? ]
log (3.555) = (Ea / (2.303R) [1/303 - 1/313]
1.268 * 8.314 * 303 * 313 = 10Ea
So, Ea = 100 kJ

New answer posted

7 months ago

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A
alok kumar singh

Contributor-Level 10

According to IUPAC convention for naming of elements with atomic number more than 100, different digits are written in order and at the end ium is added. For digits following naming is used.

0 -nil

1-un

2-bi

3-tri

and so on.

New answer posted

7 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

 

New answer posted

7 months ago

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A
alok kumar singh

Contributor-Level 10

(x/m) = k (P)¹/?
log (x/m) = log k + (1/n) log P
Slope = 1/n = 2 So n = ½
Intercept ⇒ log k = 0.477 So k = Antilog (0.477) = 3
So (x/m) = k (P)¹/? = 3 [0.04]² = 48 * 10?

New answer posted

7 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go throiugh the solution

 

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