Chemistry
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New answer posted
10 months agoContributor-Level 9
B.D.E H-H < B.D.E D-D
B.D.E H-H = 435.9 kJ / mole
B.D.E D-D = 443.4 kJ / mole
E H ≈ E D - 7.5
New answer posted
10 months agoContributor-Level 9
Gabriel phthalimide is used for the preparation of 1° aliphatic amine not 1° aromatic amines since 1° aromatic amines do not undergo nucleophilic substitution reaction.
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10 months agoContributor-Level 10
Rotamers or conformers arises due to free rotation along σ - bond.
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10 months agoContributor-Level 10
Barfoed test:-
In this test, copper acetate in dilute acid is reduced in 30 seconds by mono saccharides while disaccharides takes several minutes.
New answer posted
10 months ago
Contributor-Level 9
[Aldol condensation of 2-methylcyclopentanone with acetaldehyde to form an aldol product, which then undergoes iodoform reaction to give a carboxylic acid and iodoform.]
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10 months agoContributor-Level 10
Rate = K [A]?
K = Rate / [A]?
= (mole L? ¹s? ¹) / (mole L? ¹)?
= mole¹? L? ¹ s? ¹
Unit of K: mole¹? L? ¹ s? ¹
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10 months agoContributor-Level 10
Rutherford atomic model can not explain hydrogen spectrum it is explained by Bohr's atomic model and from Bohr's atomic model, uncertainity principle can't be explained.
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10 months ago
Contributor-Level 10
Density ∝ molar mass, as size of given molecules is nearly same
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10 months ago
Contributor-Level 9
(a) Phenol with Br? / H? O gives 2,4,6-tribromophenol. (High ionisation due to polar solvent and high activation of ring)
(b) Phenol with Br? in CS? /CHCl? /FeBr? gives a mixture of o- and p-bromophenol, with p-bromophenol as the major product. (less ionisation due to non- polar solvent)
[Chemical reactions showing bromination of phenol under different conditions]
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