Class 12th

Get insights from 12k questions on Class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 12th

Follow Ask Question
12k

Questions

0

Discussions

65

Active Users

0

Followers

New answer posted

6 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

System of equation is

(2311111|λ|) (xyz)= [244λ4]

R1 – 2 R2, R3 – R2

(0131102|λ|1) (xyz)= (1044λ8)

System of equation will have no solution for λ = 7.

New answer posted

6 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

 C0=ε0Ad

C1=4ε0Ad=4C0

CZ=kε0A34d=4kc03

Series

Ca=C1C2C1+C2

16k3dC024C0 (1+k3)

=4kC0k+3

New answer posted

6 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

 f (x)= [2nn=2, 4, 6....n1n=3, 7, 11, 15....n+12n=1, 5, 9, 13....

for n = 2, 4, 6 ……

f (n) = 4, 8, 12, ….4 (n) form

for n = 3, 7, 11, 15, ….

f (n) = 1, 3, 5, 7, …. (4n + 1) or, (4n + 3) from

 f is one and onto.

New answer posted

6 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

α (60!) (30!) (31!)=62!32!30!60!31!29!

= (1411)60! (31!) (30!)16

16α=1411

New answer posted

6 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

 mN2=14g, T=27°C=300k

To double the Vrms Tf = 4Ti = 4 * 300 = 1200 k.

Q=nCvΔT

=5*225R=1125R=1125*3.32

= 9360 J.

New answer posted

6 months ago

0 Follower 39 Views

V
Vishal Baghel

Contributor-Level 10

ρω=1000kg/m3

G = 10 m/s2

Using bernaulli's eqn

5*105π+ρg*10=ρ0+12ρVe2

=318? 17.8m/s

New answer posted

6 months ago

0 Follower 1 View

N
Nishtha

Contributor-Level 10

Candidates seeking admission to the BSc programme can enrol for admission with Class 12 marks. Candidates must complete Class 12 to enrol for the UG course. The candidate should pass Class 12 from recognised boards (AISSCE/CBSE/ICSE/SSCE/HSCE/NIOS/APOSS) or equivalent.

New answer posted

6 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

 T1T2=46=g2g1

(1+hR)2=941+hR=32h=R2=3200km.

New answer posted

6 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

m = 200 g, ki = 90 J kf = 40 J.,  Δt=1sec

F=kfkix.4*90.4*40=F*1

F=64=2N

So for complete rest :-

Fx = 90 J

2x = 90 x = 45 m

New answer posted

6 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

Mass = m

Length = L

mL=?

at l=Lx, achain=g2

a=FPullingmass= (L? l)? g? ? lg? L= (L? 2l)? g? L=g2

l=L4? x=4

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 684k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.