Class 12th

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New answer posted

11 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

α (60!) (30!) (31!)=62!32!30!60!31!29!

= (1411)60! (31!) (30!)16

16α=1411

New answer posted

11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

 mN2=14g, T=27°C=300k

To double the Vrms Tf = 4Ti = 4 * 300 = 1200 k.

Q=nCvΔT

=5*225R=1125R=1125*3.32

= 9360 J.

New answer posted

11 months ago

0 Follower 76 Views

V
Vishal Baghel

Contributor-Level 10

ρω=1000kg/m3

G = 10 m/s2

Using bernaulli's eqn

5*105π+ρg*10=ρ0+12ρVe2

=318? 17.8m/s

New answer posted

11 months ago

0 Follower 2 Views

N
Nishtha

Contributor-Level 10

Candidates seeking admission to the BSc programme can enrol for admission with Class 12 marks. Candidates must complete Class 12 to enrol for the UG course. The candidate should pass Class 12 from recognised boards (AISSCE/CBSE/ICSE/SSCE/HSCE/NIOS/APOSS) or equivalent.

New answer posted

11 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

 T1T2=46=g2g1

(1+hR)2=941+hR=32h=R2=3200km.

New answer posted

11 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

m = 200 g, ki = 90 J kf = 40 J.,  Δt=1sec

F=kfkix.4*90.4*40=F*1

F=64=2N

So for complete rest :-

Fx = 90 J

2x = 90 x = 45 m

New answer posted

11 months ago

0 Follower 21 Views

V
Vishal Baghel

Contributor-Level 10

Mass = m

Length = L

mL=?

at l=Lx, achain=g2

a=FPullingmass= (L? l)? g? ? lg? L= (L? 2l)? g? L=g2

l=L4? x=4

New answer posted

11 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Organic compound AgBr (s)

      0.5 g  0.40 g

Here; Moles of Br in organic compound = Moles of Br in Ag Br

= Moles of AgBr

0.40188mol

Mass of Br in organic compound = 0.4188*80g

%ofBr=0.4*80188*0.5*100%=34%

New answer posted

11 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

All metal carbonyls have synergic bonds.

New answer posted

11 months ago

0 Follower 67 Views

V
Vishal Baghel

Contributor-Level 10

A = 10 cm2, V = 20 m/s

F=dpdt=ρAV2=103*10*104*400

= 400 N.

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