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Hydrocarbons

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9 months ago

Hydrocarbons Class 11th

Compound X on reaction with O? followed by Zn/H?O gives formaldehyde and 2-methyl propanal as products. The compound X is:

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Vishal Baghel

Contributor-Level 10

Formaldehyde 2-methyl propanal

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10 months ago

Hydrocarbons Class 11th

1-methyl ethylene oxide when treated with an excess of , produces

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New answer posted

10 months ago

Hydrocarbons Class 11th

In $\overset{1}{C} H_{2} = \overset{2}{C} = \overset{3}{C} H - \overset{4}{C} H_{3}$ molecule, the hybridization of carbon 1,2,3 and 4 respectively are:

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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10 months ago

Hydrocarbons Class 11th

The formula of a gaseous hydrocarbon which requires 6 times of its own volume of O₂for complete oxidation and produces 4 times its own volume of CO₂ is C_xH_y. The value of y is…………….

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Vishal Baghel

Contributor-Level 10

$C_{x} H_{y} (g) + (x + \frac{y}{4}) O_{2} (g) \to x C O_{2} (g) + \frac{y}{2} H_{2} O (l)$

V 6V - -

- - 4V

Volume of CO2 = 4 * $V_{C_{x} H_{y}}$ $_{_{}_{}}$

Vx = 4V

x = 4

Volume of O2 = 6 * $V_{C_{x} H_{y}}$ $_{_{}_{}}$

$V (x + \frac{y}{4}) = 6 V$

$4 + \frac{y}{4} = 6$

y = 8

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10 months ago

Hydrocarbons Class 11th

Which one of the following carbonyl compound cannot be prepared by addition of water on an alkyne in the presence of HgSO₂ and H₂SO₄?

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Vishal Baghel

Contributor-Level 10

Hence

CH₃ – CH₂ – CHO can't be formed.

In case of unsymmetrical alkynes, more positive charge stabilizing carbon attacked by H₂O and finally converted into carbonyl.

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11 months ago

Hydrocarbons Class 11th

In the following structures, which one is a having staggered conformation with maximum diheldral angle?

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Vishal Baghel

Contributor-Level 10

(A) and (C) are staggered conformation. In (A) dihedral angle is 60° and in (C) dihedral angle is 180°.

Dihedral angle is angle between two specified groups.

In (C) it has maximum angle.

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New answer posted

11 months ago

Hydrocarbons Chemistry NCERT Exemplar Solutions Class 12th Chapter Thirteen

Two isomers 'A' and 'B' with molecular formula C₄H₈ give different products on oxidation with KMnO₄ is acidic medium. Isomer 'A' on reaction with KMnO₄/H⁺ results in effervescence of a gas and given ketone. The compound 'A' is