Chemistry NCERT Exemplar Solutions Class 12th Chapter Four

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J
Jaya Sinha

Beginner-Level 5

As you know, electrovalent bonds result very strong electrostatic attraction force. All the factors that help maximize this electrostatic attraction are important for the formation of the ionic bond. Here are the important factors;

  • Low ionization energy Metal
  • High electron affinity Non Metal
  • Large-sized cations
  • Small-sized anions
  • Electronegativity equal to or greater than 1.7

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

New answer posted

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

New answer posted

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

New answer posted

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

New answer posted

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

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P
Payal Gupta

Contributor-Level 10

Radius of Bohr's orbit Rn=0.529Ao*n2z

Radius of Bohr's orbit for hydrogen,  Rn=0.529Ao*n2

For third orbit (R3) = 0.529Ao*9 = r3 and

Fourth orbit (R4) = 0.59Ao*16=r4

r4=16r39

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A
alok kumar singh

Contributor-Level 10

Covalent character is LiCl>NaCl>KCl>CsCl. As the cationic size increases polarization decreases.

 Covalent character decreases.

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A
alok kumar singh

Contributor-Level 10

Covalent character is L i C l > N a C l > K C l > C s C l .  As the cationic size increases polarization decreases.

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A
alok kumar singh

Contributor-Level 10

t1/2 = 200 sec and it is 1st order reaction

K=2.303log2200=2.303tlogCo0.2Co

log2200=1tlog5

t=73*200=466.67sec=467sec

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