Chemistry

Contributor-Level 9

Please consider the following Image

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The correct pair(s) of the ambident nucleophiles is (are):
(A) AgCN / KCN
(B) RCOOAg / RCOOK
(C) AgNO2 / KNO2
(D) Agl / KI

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Chemistry Chemistry Chemical Kinetics

Contributor-Level 10

CN? and NO? are examples of ambident nucleophiles.

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During which of the following processes, does entropy decrease?
(A) Freezing of water to ice at 0°C
(B) Freezing of water to ice at -10°C
(C) N2(g) + 3H2(g) → 2NH3(g)
(D) Adsorption of CO(g) on lead surface
(E) Dissolution of NaCl in water
Choose the correct answer from the options given below:

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Contributor-Level 10

The change in entropy for the following processes is negative (ΔS = -ve), indicating an increase in order:

Water (l) → Ice (s) at 0°C

H? O (l) → Ice (s) at -10°C

N? (g) + 3H? (g) → 2NH? (g)

Adsorption

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9 months ago

Kindy consider the following

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Chemistry Ncert Solutions Chemistry Class 11th

Contributor-Level 10

The reaction shown is:
Anisole diazonium chloride (A) + Ethanol → Anisole + Acetaldehyde (X) + HCl + N? (Y)

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Considering the above chemical reaction, identify the product "X":

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Contributor-Level 9

Please consider the following Image

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One of the by-products formed during the recovery of NH₃ from solvay process is:

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Contributor-Level 10

The reactions in the Solvay process are:

NaCl + H? O + NH? + CO? → NH? Cl + NaHCO?

2NaHCO? → Na? CO? + CO? + H? O

2NH? Cl + Ca (OH)? → CaCl? + 2NH? + H? O

CaCl? is a byproduct of the process.

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9 months ago

Match List - I with List - II
List - I
(a) Chlorophyll
(b) Vitamin B?
(c) Anticancer drug
(d) Grubbs catalyst

List - II
(i) Ruthenium
(ii) Platinum
(iii) Cobalt
(iv) Magnesium

Choose the most appropriate answer from the options given below:

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Contributor-Level 9

o Chlorophyll: Magnesium present in chlorophyll.

o Vitamin B? : Cobalt (cyanocobalamin).

o Anticancer drug: Platinum (Coordination compound of platinum).

o Grubbs catalyst: Ruthenium.

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Chemistry Class 11th

Kindly consider the following

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Contributor-Level 10

The addition of HBr to H? C−CH? −CH=CH? proceeds via carbocation formation.

Formation of a 1° Carbocation (A): H? C−CH?

Formation of a 2° Carbocation (B): H? C−CH? −C? H−CH?

The 2° carbocation (B) is more stable than the 1° carbocation (A). Therefore, the activation energy (Ea) for the formation of B is lower, and B is formed faster.

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Chemistry Class 11th

Match List - I with List - II:
List - I (Chemicals)
(a) Alcoholic potassium hydroxide
(b) Pd/BaSO?
(c) BHC (Benzene hexachloride)
(d) Polyacetylene

List - II (Use / Preparation / Constituent)
(i) electrodes in batteries
(ii) obtained by addition reaction
(iii) used for β-elimination reaction
(iv) Lindlar's Catalyst

Choose the most appropriate match:

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Contributor-Level 9

o Alcoholic potassium hydroxide (Alc KOH):- used for β - elimination.

o Pd / BaSO? : - Lindlar's Catalyst.

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Chemistry Class 11th

The set of elements that differ in mutual relationship from those of the other sets is:

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