Chemistry

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New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

P? + 3NaOH + 3H? O → PH? + 3NaH? PO? (A)
Here, NaH? PO? is a reducing agent.
NaH? PO? + AgNO? + H? O → Ag + HNO? + NaH? PO?
Equivalents of NaH? PO? = equivalents of Ag (n-factor of NaH? PO? = 4)
1 mole * 4 = n moles of Ag * 1
So, moles of Ag = 4.

New answer posted

10 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

For the weak acid HA in the presence of strong acid HCl:
Ka = [ (Cα + 0.1) * Cα] / [C (1-α)] ≈ (0.1 * 10? ²α) / 10? ² = 0.1α
Given Ka = 2 * 10?
2 * 10? = 10? ¹ * α
α = 2 * 10?
Ans = 2

New answer posted

10 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Mole of CH? = 6.4 / 16 = 0.4 and mole of CO? = 8.8 / 44 = 0.2
Total mole = (0.4 + 0.2) = 0.6 mole of a non-reacting mixture of gas
Using Ideal Gas Law; P = nRT / V
P = (0.6 * 8.314 * 300) / 10 = 149.65 kPa
Ans = 150 (Rounded off)

New answer posted

10 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Kt = 2.303 log? (A? /A? )
K * 570 = 2.303 log? (100/32)
K = [2.303 / 570] [log?10² - log?2? ]
K = [2.303 / 570] [2 - 5 * 0.301] = [2.303 / 570] * 0.495 = 0.002 = 2.0 * 10? ³ s? ¹
Ans = 2

New answer posted

10 months ago

0 Follower 18 Views

V
Vishal Baghel

Contributor-Level 10

Partial Pressure of O? = K? * solubility (K? = Henry's constant)
Solubility = PO? / K? = 20 / (8.0 * 10? ) = 2.5 * 10? = 25 * 10? M
Ans = 25

New answer posted

10 months ago

0 Follower 26 Views

V
Vishal Baghel

Contributor-Level 10

In an aromatic compound, overall delocalization is processed by the electrons according to Hückel's rule. For the compound in question, the total number of delocalized electrons is 6.

New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

At the point of intersection in an Ellingham diagram? G for two processes becomes equal, so? G for the reduction becomes zero. A sudden increase in the slope indicates a change in the state of the metal oxide, i.e., from solid to liquid or liquid to vapor.

New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

In the ammonolysis process, bond cleavage is carried out in the presence of NH? When a halide compound is treated with NH? , the halide ion (X? ) is substituted by an amino group (NH? ) in a nucleophilic substitution reaction.

New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

A more reactive carbonyl, i.e., a ketone, is masked with ethylene glycol first in an acidic medium.

New answer posted

10 months ago

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V
Vishal Baghel

Contributor-Level 10

Allosteric inhibitors are a type of drug-enzyme inhibitor that binds to a site other than the active site of the enzyme, causing a conformational change that affects the active site. The statement in the document incorrectly states they bind at the active site due to steric factors.

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