Chemistry
Get insights from 6.9k questions on Chemistry, answered by students, alumni, and experts. You may also ask and answer any question you like about Chemistry
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
10 months agoContributor-Level 10
The reaction is: FeCl? + 3H? C? O? + 3KOH → K? [Fe (C? O? )? ] (A) + 3HCl + 3H? O
In the complex [Fe (C? O? )? ]³? , the oxalate ion (C? O? )²? is a bidentate ligand.
There are three bidentate ligands, so the coordination number, or secondary valency, of Fe is 3 * 2 = 6.
New answer posted
10 months agoContributor-Level 10
The cell constant (G) is given by G = κ * R, where κ is conductivity and R is resistance.
Since the cell constant is constant: (κ * R)KCl = (κ * R)HCl
0.14 Sm? ¹ * 4.19 Ω = κ_HCl * 1.03 Ω
κ_HCl = (0.14 * 4.19) / 1.03 = 0.569 Sm? ¹
This is equivalent to 56.9 * 10? ² Sm? ¹.
The answer, rounded off, is 57.
New answer posted
10 months agoContributor-Level 10
-SO? H acts as a cation exchanger.
-NH? acts as an anion exchanger.
New answer posted
10 months agoContributor-Level 10
3CaO + 2Al → 3Ca + Al? O?
ΔH? = ΣΔH? (Products) - ΣΔH? (Reactants)
ΔH? = [ (0) + (-1675) ] - [ (3 * -635) + (0) ]
ΔH? = -1675 - (-1905) = -1675 + 1905 = 230 kJ
Ans = 230
New answer posted
10 months agoContributor-Level 10
Moles of benzene = 3.9 g / 78 g/mol . This would produce (3.9 / 78) moles of nitrobenzene in 100% conversion.
Produced moles of nitrobenzene = 4.92 g / 123 g/mol .
% yield = [ (4.92 / 123) / (3.9 / 78) ] * 100 = [ (4.92 * 100 * 78) / (123 * 3.9) ] = 80.0%
Ans = 80
New answer posted
10 months agoContributor-Level 10
Molality = (mole of solute * 1000) / wt of solvent (gm)
100 = (n_solute * 1000) / [ (1 - n_solute) * 18]
(1 - n_solute) / n_solute = 1000 / (100 * 18) = 10/18
18 (1 - n_solute) = 10 n_solute
18 - 18 n_solute = 10 n_solute
18 = 28 n_solute
n_solute = 18 / 28? 0.6428 = 64.28 * 10? ²
Ans = 64 (Rounded off)
New answer posted
10 months agoContributor-Level 10
For n = 4, the possible values of l are 0, 1, 2, 3.
For l = 3, and m = -3.
Radial nodes = (n - l - 1) = (4 - 3 - 1) = 0
Ans = 0
New answer posted
10 months agoContributor-Level 10
Cr? O? ²? + Fe²? - (H? )-> Cr³? + Fe³?
(n=6) (n=1)
Meq Cr? O? ²? = Meq Fe²?
20 * 0.03 * 6 = 15 * M * 1
M = (20 * 0.03 * 6) / 15 = 0.24 = 24 * 10? ²
Ans = 24
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 702k Reviews
- 1850k Answers




