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New answer posted

4 months ago

0 Follower 15 Views

A
alok kumar singh

Contributor-Level 10

The reaction is N? O? (g)? 2NO? (g).

Δn_g = (moles of gaseous products) - (moles of gaseous reactants) = 2 - 1 = 1.

The relationship between Kp and Kc is Kp = Kc (RT)^Δn_g.

600.1 = 20.4 * (0.0831 * T)¹

T = 600.1 / (20.4 * 0.0831) = 353.99 K.

The answer, rounded off, is 354 K.

New answer posted

4 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

Using the Ideal Gas Law, PV = nRT:

P = 1 bar

V = 20 mL = 0.020 L

R = 0.083 L·bar·mol? ¹·K? ¹

T = 273 K

n = PV / RT = (1 * 0.020) / (0.0831 * 273) = 8.8 * 10? mol of Cl?

Number of Cl? molecules (N) = n * N_A = (8.8 * 10? ) * (6.022 * 10²³) = 5.3 * 10²? molecules.

Number of Cl atoms = 2 * (5.3 * 10²? ) = 1.06 * 10²¹.

The answer, rounded off to the nearest integer for the power of 10²¹, is 1.

New answer posted

4 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

For the dissociation of K? [Fe (CN)? ]? 4K? + [Fe (CN)? ]? , the number of ions produced (n) is 5.

The degree of dissociation (α) is related to the van't Hoff factor (i) by α = (i-1)/ (n-1).

Given α = 0.4: 0.4 = (i - 1) / (5 - 1) => 1.6 = I - 1 => I = 2.6

Using the depression in freezing point formula (ΔTf = i·Kf·m), and equating the ΔTf for two different solutions:
ΔTf (K? [Fe (CN)? ]) = ΔTf (A)
i? ·Kf·m? = i? ·Kf·m?
(2.6) * [ (18.1 / M) / (100-18.1)/1000] = (1) * [ (w? /M? ) / (W? /1000)]
The problem simplifies to finding the molar mass M of solute A:
2.6 * [18.1 / (M * 81.9)] * 1000 = [w? /M? ] * [1000/W? ]
Assuming the secon

...more

New answer posted

4 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

The reaction is: FeCl? + 3H? C? O? + 3KOH → K? [Fe (C? O? )? ] (A) + 3HCl + 3H? O

In the complex [Fe (C? O? )? ]³? , the oxalate ion (C? O? )²? is a bidentate ligand.

There are three bidentate ligands, so the coordination number, or secondary valency, of Fe is 3 * 2 = 6.

New answer posted

4 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

The cell constant (G) is given by G = κ * R, where κ is conductivity and R is resistance.

Since the cell constant is constant: (κ * R)KCl = (κ * R)HCl

0.14 Sm? ¹ * 4.19 Ω = κ_HCl * 1.03 Ω

κ_HCl = (0.14 * 4.19) / 1.03 = 0.569 Sm? ¹

This is equivalent to 56.9 * 10? ² Sm? ¹.

The answer, rounded off, is 57.

 

New answer posted

4 months ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

4 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

4 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

-SO? H acts as a cation exchanger.

-NH? acts as an anion exchanger.

New answer posted

4 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

3CaO + 2Al → 3Ca + Al? O?
ΔH? = ΣΔH? (Products) - ΣΔH? (Reactants)
ΔH? = [ (0) + (-1675) ] - [ (3 * -635) + (0) ]
ΔH? = -1675 - (-1905) = -1675 + 1905 = 230 kJ
Ans = 230

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Moles of benzene = 3.9 g / 78 g/mol . This would produce (3.9 / 78) moles of nitrobenzene in 100% conversion.
Produced moles of nitrobenzene = 4.92 g / 123 g/mol .
% yield = [ (4.92 / 123) / (3.9 / 78) ] * 100 = [ (4.92 * 100 * 78) / (123 * 3.9) ] = 80.0%
Ans = 80

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