Chemistry

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New answer posted

10 months ago

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J
Jaya Sinha

Beginner-Level 5

As you know, electrovalent bonds result very strong electrostatic attraction force. All the factors that help maximize this electrostatic attraction are important for the formation of the ionic bond. Here are the important factors;

  • Low ionization energy Metal
  • High electron affinity Non Metal
  • Large-sized cations
  • Small-sized anions
  • Electronegativity equal to or greater than 1.7

New answer posted

10 months ago

0 Follower 2 Views

N
Nishtha Datta

Beginner-Level 5

Covalent and electrovalent bonding are the two major chemical bonding processes. These two bonds are different from each other in multiple aspects. Check the table below to know a concise summary of the differences.

ParticularCovalent BondIonic Bond
FormationDue to the complete transfer of electronsDue to the sharing of electron pairs
Ion formationNo ions formedCations and Anions formed.
NatureElectrostatic attraction between ionsElectrostatic attraction between nuclei and shared electrons
Strength StrongLess strong
Melting/Boiling pointHigh due to a strong bondlower due to weaker bond
PolarityHighley PolarNon-Polar

New answer posted

10 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

New answer posted

10 months ago

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A
alok kumar singh

Contributor-Level 10

The structure of the given compound is as show below

 

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10 months ago

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A
alok kumar singh

Contributor-Level 10

ΔG° = –nFE°
∴ 17.37 x 10³ = –3 x 96500 x E°
∴ E° = –6 x 10? ² V

New answer posted

10 months ago

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A
alok kumar singh

Contributor-Level 10

C? H? + 5O? → 3CO? + 4H? O
C? H? + (13/2)O? → 4CO? + 5H? O
∴ 2 mol C? H? is given
∴ 13 mol O? is required for combustion of Butane
∴ Total mol of O? = 5 + 13 = 18

New answer posted

10 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

10 months ago

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A
alok kumar singh

Contributor-Level 10

Ellingham diagram provides information on Gibb's free energy for formation of oxides as a function of temperature.

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10 months ago

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A
Aadit Singh Uppal

Contributor-Level 10

Industries manily select an optimal temperature which is high enough to increase the reaction rate (molecules colliding with each other at higher fequencies) and at the same time is balanced to avoid any side effect. This effectively yields high quality production without any wastage or leading to harmful results while ensuring safety of the consumers too.

New answer posted

10 months ago

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A
alok kumar singh

Contributor-Level 10

Gd: [Xe]4f?5d¹6s²
∴ Gd³? is [Xe]4f?
Also μ = √n (n + 2) B.M
= √7x9 B.M = 7.9 B.M

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