B.Tech in Roorkee

Candidates must have completed their 10+2 education with Physics and Mathematics as compulsory subjects, along with Chemistry/Biology/Biotechnology/Technical Vocational as one of the optional subjects for eligibility. Along that they should have obtained a minimum  score of 45% in the qualifying examination.

Infrastructure:

Both the university have good infrastructure. If you consider WiFi then you can get on both the campus. Also, they provide Library, Canteen, Hostels for both Boys and Girls.

Courses:

Coer university provides a total of 38 courses, where as Haridwar University provides a total of 70 courses.

Placement:

Considering previous year placements Haridwar University performs better than COER university. In Haridwar University around 90% students get placed where as COER university student's placement rate is 70-80%.

Conclusion

i would recommend to go for Haridwar University as it has better stats than COER university

B.Tech at COER Roorkee you need to give the JEE MAINS exam and get at least 50 percentile in that as the closing rank is near about 5,00,000.

Thus for 50 percentile, you need 31-40 marks out of 300 and for Computer Science you need 70 percentile i.e 41-50 marks out of 300.

While COER is an engineering college and provides campus placement but it is not as good as IITs or NITs. You can opt this college as it has a median salary of 5.14 LPA in campus placements so after IITs and NITs, this college is a decent option.

For B.Tech at COER University Roorkee you need to clear the JEE MAINS Exam with atleast 50 percentile marks as the cutoffs goes low as 500000 for general category. The cutoff for Computer Science Engineering closes at around 300000 to 325000. You need to go through the uttrakhand engineering admissions counselling.