Colleges in Delhi
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New answer posted
5 months agoContributor-Level 10
Ecole Intuit Lab, New Delhi offers both merit and entrance based admission to its BVoc programme. The students may get selected without a valid UCEED score as well. However, the candidates may have to go through other selection rounds.
New answer posted
5 months agoContributor-Level 10
As per NIRF report 2025, Department of Law MDU placements 2024 are mentioned below:
Course | Median Package 2024 | Placement Rate 2024 |
|---|---|---|
BA LLB | INR 1.25 LPA | 100% |
LLB | INR 1.25 LPA | 100% |
LLM | INR 8.4 LPA | 100% |
New answer posted
5 months agoContributor-Level 10
Ecole Intuit Lab, New Delhi offers UG and PG programmes. The courses are as below:
- UG Game Art & Design
- UG Visual Communication
- UG UI/UX Design
- UG Animation & Motion Design
- PG Advertising, Design & Digital Communication
New answer posted
5 months agoContributor-Level 10
Students at Ecole Intuit Lab, New Delhi get selected through several selection rounds. The college considers UCEED/ CEED scores. The final selection is based on - Creative Aptitude Test + Porftolio Review + Personal Interview.
New answer posted
5 months agoContributor-Level 10
Ecole Intuit Lab, New Delhi generally does not offer direct admissions. Students have to appear for the selection rounds and clear the same to get admission. The selection process includes Creative Aptitude Test + Porftolio Review + Personal Interview.
New answer posted
5 months agoNew answer posted
5 months agoContributor-Level 10
Jamia Hamdard University Delhi placement assistance is given to students. Jamia Hamdard is visited by top companies for placements such as TCS, Infosys, Pfizer, and others. Over the years, there has been a rise in the placements offered to students.
New answer posted
5 months agoContributor-Level 10
JNU CCMT cutoff 2025 was based on the results for the GATE exam, followed by the CCMT counselling process. For the M.Tech Computer Science and Technology course, the overall cutoff ranged from 529 to 338 for the OBC AI category.
Candidates can refer to the table below to know the cutoff range for different All India categories.
| Category | JNU M.Tech cutoff 2025 Range |
|---|---|
| General | 592 - 350 |
| SC | 280 - 393 |
| ST | 256 - 350 |
| EWS | 417 - 325 |
| PWD | 252 |
| OBC | 529 - 338 |
New answer posted
5 months agoContributor-Level 10
The JNU M.Tech cutoff 2025 for the OBC AI category varied from 338 to 529 for the M.Tech CSE and M.Tech ECE courses. In the last round, MTech CSE came out as the more competitive course, with the cutoff being 443.
Students can refer to the table below to know the round 1 and last round JNU CCMT cutoff 2025 for the OBC AI category.
| Course | Round 1 (Closing Score) | Last Round (Closing Score) |
|---|---|---|
| MTech in Computer Science and Engineering | 529 | 443 |
| M.Tech in Electronics and Communication Engineering | 362 | 338 |
New answer posted
5 months agoContributor-Level 10
JNU cutoff 2025 was released for the M.Tech course admission for various All India categories based on the GATE entrance examination, followed by the CCMT counselling process.
To get a seat at JNU, students have to appear for the GATE exam, attain a valid score and then participate in the CCMT counselling process to be eligible to pursue the M.Tech course. For the General AI category, the overall cutoff ranged from 350 to 592, wherein, in the last round, MTech CSE was the most competitive course branch for admission.
Note: Other categories will have different cutoffs accordingly.
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