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New answer posted
3 months agoContributor-Level 10
To get a seat at Lokmanya Tilak College of Engineering for the BE course branches, students have to appear for the MHT CET entrance examination, followed by the counselling process for to be considered eligible for admission.
The Lokmanya Tilak College of Engineering MHT CET cutoff 2024 was released in the form of opening and closing percentiles for various Home State quota categories.
New answer posted
3 months agoContributor-Level 10
Lokmanya Tilak College of Engineering cutoff 2024 for the BTech CSE branch varied from 86.82 to 91.63 for the General HS category. According to the last round, the most and least competitive engineering branches for admission were BE CSE (Data Science) and BE in Computer Science and Engineering (Internet of Things and Cyber Security, including Blockchain Technology), respectively.
Students can refer to the table below to know the round 1 and last round cutoff percentiles for all CSE branches.
| Course | Round 1 (Closing Percentiles) | Last Round (Closing Percentiles) |
|---|---|---|
| B.E in Computer Science and Engineering (Internet of Things and Cyber Security Including Block Chain Technology) | 86.82 | 88.02 |
| B.E in Computer Science and Engineering (Artificial Intelligence and Machine Learning) | 87.16 | 88.7 |
| B.E in Computer Science and Engineering (Data Science) | 88.6 | 91.63 |
New answer posted
3 months agoContributor-Level 10
No, you cannot get admission to this institute based on the Lokmanya Tilak College of Engineering BE cutoff 2024 if you belong to the General HS quota.
For the General category students belonging to the Home State category, the overall cutoff varied between 69.63 and 91.63. Hence, students who belong to this category need to attain a score between this range.
Note: This is the cutoff range for the General HS category; other categories will have different cutoffs accordingly.
New answer posted
3 months agoContributor-Level 10
AFI requires applicants to submit a narrative statement of no longer than 3 pages in length and containing the points mentioned below-
- Personal story- What shaped applicant as person
- Discipline of Interest- Why applicant wants to apply to specific program. What movie, person or art piece inspired them
- Collaboration experience
- Long-term goals- Including AFI Conservatory's role
New answer posted
3 months agoContributor-Level 10
Lokmanya Tilak College of Engineering MHT CET cutoff 2024 was released for admission to the BE course for various categories belonging to the Home State quota.
For the General HS category, the overall cutoff ranged from 69.63 to 91.63. According to the last round, the hardest BE course branch was BE in Computer Science and Engineering (Data Science). Students can refer to the click here to know more about the Lokmanya Tilak College of Engineering BTech cutoff 2024.
New answer posted
3 months agoGuide-Level 15
SGT University considers JEE Main scores for admission to BTech. Candidates are also selected for BTech courses based on their merit or CUET scores. However, the preference is given to candidates with JEE Main scores.
New answer posted
3 months agoContributor-Level 10
JNU CCMT cutoff 2025 was based on the results for the GATE exam, followed by the CCMT counselling process. For the M.Tech Computer Science and Technology course, the overall cutoff ranged from 529 to 338 for the OBC AI category.
Candidates can refer to the table below to know the cutoff range for different All India categories.
| Category | JNU M.Tech cutoff 2025 Range |
|---|---|
| General | 592 - 350 |
| SC | 280 - 393 |
| ST | 256 - 350 |
| EWS | 417 - 325 |
| PWD | 252 |
| OBC | 529 - 338 |
New answer posted
3 months agoContributor-Level 10
The JNU M.Tech cutoff 2025 for the OBC AI category varied from 338 to 529 for the M.Tech CSE and M.Tech ECE courses. In the last round, MTech CSE came out as the more competitive course, with the cutoff being 443.
Students can refer to the table below to know the round 1 and last round JNU CCMT cutoff 2025 for the OBC AI category.
| Course | Round 1 (Closing Score) | Last Round (Closing Score) |
|---|---|---|
| MTech in Computer Science and Engineering | 529 | 443 |
| M.Tech in Electronics and Communication Engineering | 362 | 338 |
New answer posted
3 months agoContributor-Level 10
JNU cutoff 2025 was released for the M.Tech course admission for various All India categories based on the GATE entrance examination, followed by the CCMT counselling process.
To get a seat at JNU, students have to appear for the GATE exam, attain a valid score and then participate in the CCMT counselling process to be eligible to pursue the M.Tech course. For the General AI category, the overall cutoff ranged from 350 to 592, wherein, in the last round, MTech CSE was the most competitive course branch for admission.
Note: Other categories will have different cutoffs accordingly.
New answer posted
3 months agoContributor-Level 10
For general students 60 marks is not good enough for admission in top NITs or IIITs. 60 marks will be around 80 percentile and will give rank between 1.5 and 2.5 lakhs.
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