B.Tech Cut-off
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New answer posted
2 years agoContributor-Level 10
Yes, it is not possible to get a CSE seat at CMR College of Engineering and Technology with a TS EAMCET closing rank of 16000. In 2025, for CSE admission, the cutoff ranged from 6477 to 49403 for the students belonging to the General AI category. However, in the initial round, the cutoffs are more competitive for admission. Therefore, students have to wait till the last round.
New answer posted
2 years agoContributor-Level 10
CRM College of Engineering accepts TS EAMCET entrance exam scores for admission to the B.Tech. courses. For the General AI category, the overall TS EAMCET closing ranks ranged between 6477 and 49403. The cutoff ranks vary for different rounds and categories. Refer to the table below to view the TS EAMCET first and last round closing ranks for General AI category students:
Course | Round 1 (Closing Rank) | Last Round (Closing Rank) |
|---|---|---|
B.Tech. in Civil Engineering | 40084 | 40084 (R1) |
B.Tech. in Computer Science and Engineering | 12836 | 13817 |
B.Tech. in Computer Science and Engineering (Artificial Intelligence and Machine Learning) | 13742 | 15118 |
B.Tech. in Computer Science and Engineering (Data Science) | 14772 | 15512 |
B.Tech. in Electrical and Electronics Engineering | 27286 | 33269 |
B.Tech. in Electronics and Communication Engineering | 18565 | 20275 |
B.Tech. in Mechanical Engineering | 38586 | 38586 (R1) |
New answer posted
2 years agoContributor-Level 10
Jyothy Institute of Technology accepts COMEDK scores for admission to the BE/BTech courses. As per the Round 2 of the COMEDK cutoff 2024, the ranks ranged between 82308 and 99899 wherein Computer Science and Engineering was the most competitive specialisation. So yes, candidates with a cutoff rank up to 10001 can get admission at JIT.
To know what all BE/ BTech courses are available up to 10001 rank at Jyothy Institute of Technology, refer to the table below:
| Course | 2024 |
|---|---|
| B.E. in Computer Science and Engineering | 99899 |
| B.E. in Information Science and Engineering | 93842 |
| B.E. in Artificial Intelligence and Machine Learning | 82308 |
New answer posted
2 years agoContributor-Level 10
Maharaja Institute of Technology, Mysore accepts COMEDK scores for admission to the BE/BTech courses. As per the Round 2 of the COMEDK cutoff 2024, the ranks ranged between 77387 and 99974 wherein B.E. in Mechanical Engineering was the most competitive specialisation. So yes, candidates with a cutoff rank up to 91758 can get admission at Maharaja Institute of Technology.
To know what all BE/ BTech courses are available up to 91758 rank at Maharaja Institute of Technology, refer to the table below:
| Course | COMEDK Cutoff 2024 |
|---|---|
| B.E. in Mechanical Engineering | 77387 |
| B.Tech. in Computer Science and Engineering (Artificial Intelligence &Machine Learning) | 78981 |
| B.Tech. in Computer Engineering | 83748 |
| B.E. in Computer Science and Engineering | 85186 |
| B.Tech in Computer Science and Engineering (Artificial Intelligence) | 88123 |
| B.E. in Civil Engineering | 91758 |
New answer posted
2 years agoContributor-Level 10
PES Institute of Technology and Management accepts COMEDK scores for admission to the BE/BTech courses. As per the Round 2 of the COMEDK cutoff 2024, the ranks ranged between 54016 and 100785, wherein B.Tech. in Artificial Intelligence and Machine Learning was the most competitive specialisation. So yes, candidates with a cutoff rank of up to 5000 can get admission at PESITM in AI and Machine Learning.
New answer posted
2 years agoContributor-Level 10
Government College of Engineering and Ceramic Technology WBJEE cutoff 2025 was released for admission to the B.Tech. course. For the General HS category students, the last round cutoff ranged between 4539 and 13949. Refer to the table below to view the branch-wise cutoff ranks for the General category.
| Course | Last Round Cutoff 2025 |
|---|---|
| B.Tech. in Ceramic Technology | 13949 |
| B.Tech. in Information Technology | 6914 |
| B.Tech. in Computer Science and Engineering | 4539 |
New answer posted
2 years agoContributor-Level 10
IIT Dhanbad cutoff 2024 has been released for BTech, Integrated BTech and BArch courses in the form of opening and closing ranks. In Round 5, the closing ranks varied between 3846 and 16011 wherein B.Tech. in CSE is highly competitive among General category students under the AI Quota.
While comparing the IIT Dhanbad CSE cutoff 2024 with the last two years, we can see that B.Tech. in CSE has shown a declining trend in its Round 5 closing ranks. The Round 5 cutoff for the same course was 3008 in 2023 and 2888 in 2022 for the General category students for the AI Quota.
For th
New answer posted
2 years agoContributor-Level 10
IIT Dhanbad B.Tech admission is based on JEE Advanced Cutoff ranks. The IIT Dhanbad JEE Advanced Cutoff 2024 was out for Round 5, for admission to various B.Tech courses. The toughest course to get into the college for the General AI category candidates was Computer Science and Engineering, with the closing Cutoff rank of 3846. The easiest course for the General AI category was B.Tech. in Mining Machinery Engineering, with the closing cutoff rank of 15321.
Candidates can check the table provided below to check the IIT Dhanbad B.Tech Cutoff for the General AI category candidates:
New answer posted
2 years agoContributor-Level 10
IMU Visakhapatnam has released the Round 1 and Round 2 cutoff of IMU CET for admission to Naval Architecture courses. The institte accepts IMU CET entrance exam scores for admission BTech courses. During the IMU Vizag 2024 cutoff, the Round 2 closing ranks were 1930 and 2085 for BTech in Naval Architecture and Ship Building and BTech in Naval Architecture and Ocean Engineering courses for the General AI category students. So, considering the Round 2 cutoff, candidates with IMU CET rank of 1,737 are eligible to get admission at IMU Vizag for Naval Architecture courses.
Refer to the table below to check out the IMU CET Round 2 closi
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