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New answer posted

2 years ago

0 Follower 13 Views

B
Bhupinder Kour

Contributor-Level 10

To get admission to the Computer Science Engineering (CSE) or Electronics and Communication Engineering (ECE) branch at SASTRA University, you need to meet the eligibility criteria and follow the admission process.

Eligibility Criteria:

  • JEE Mains Score: You have a percentile of 90.54, which is above the average cutoff. However, the exact cutoff for SASTRA University is not publicly available. It is recommended to check the university's website for the latest cutoff information.
  • IPE Marks: You have an IPE score of 969, which is above the average cutoff. However, the exact cutoff for SASTRA University is not publicly available. It is recomm
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New answer posted

2 years ago

0 Follower 6 Views

Shiksha Ask & Answer
Indrani Choudhury

Contributor-Level 10

No, admission to BCom course is based on merit in the last qualifying exam at Satish Pradhan Dnyansadhana College. Candidates must pass Class 12 from Commerce stream to apply for the BCom course. However, only after the verification of document and payment of course fee, admission is confirmed. Any aspirant found with false documents will not be given admission.

New answer posted

2 years ago

0 Follower 72 Views

B
Bhupinder Kour

Contributor-Level 10

You would be eligible to appear for the NEET exam in 2024 if you meet the following criteria:

You have passed your 12th standard examination with Physics, Chemistry, Biology, and English as compulsory subjects. For the General category, you need to have secured a minimum of 50% marks in the aggregate of Physics, Chemistry, and Biology in your 12th standard exam. 

With the marks you mentioned - 77 in Physics, 88 in Chemistry, and 74 in Biology - your aggregate score would be 239 out of 300, which is 79.67%. This meets the 50% minimum requirement for the General category. You must have completed 17 years of age at the time of ad

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New answer posted

2 years ago

0 Follower 23 Views

Y
Yatendra Kumar

Contributor-Level 10

IIIT Kota M.Tech cutoff 2024 has been released across multiple specialisations. Based on the Round 1 seat allotment, the M.Tech cutoff scores ranged between 494 and 494 for the General AII India category students. 

Talking about AI and DS branch, the candidates must have a GATE score of 494 to get into IIIT Kota in 2024. However, with a GATE score of 437 in the OBC AI category, candidates can opt for M.Tech. in Artificial Intelligence and Data Science. Candidates seeking admission can refer to the table below to check out the closing ranks of available courses for various categories in 2024:

CourseGeneralOBCSCEWS
M.Tech. in Artificial Intelligence and Data Science494437320433

New answer posted

2 years ago

0 Follower 33 Views

B
Bhupinder Kour

Contributor-Level 10

Yes, you can get admission to the Electronics and Communication Engineering (ECE) branch at SASTRA University with 97.5% in board exams and 76 percentile in JEE Mains. The admission process at SASTRA University considers both JEE Mains scores and board exam percentages equally, with a 50:50 weightage. This means that your high board percentage and decent JEE Mains score will contribute positively to your overall admission chances.

However, please note that the admission process also depends on the number of applicants and the cutoffs set by the university. The cutoffs for ECE are generally high, but with your board percentage and JEE Ma

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New answer posted

2 years ago

0 Follower 10 Views

N
Neha Arora

Contributor-Level 10

NIT Surathkal GATE Cutoff 2024 has been released for Round 1. The most competitive course was M.Tech in CSE. The Cutoff score for CSE stood at 742, for the General AI category candidates. Therefore, candidate with the Cutoff score of 741 cannot get CSE at NIT Surathkal. However, Cutoff score of 741 can be considered for various other courses such as M.Tech in IT, M.Tech in VLSI Design, etc. 

For the OBC AI category candidates, the Cutoff score for CSE closed at 701. Candidates can refer to the table provided in this section to view the NIT Surathkal M.Tech Cutoff scores for different categories. 

 

New answer posted

2 years ago

0 Follower 24 Views

B
Bhupinder Kour

Contributor-Level 10

Based on the cutoff ranks provided, it is highly unlikely that you would get admission in the CSE branch at UIET KUK with a rank of 110000 in JEE Main. The lowest cutoff rank for the CSE branch in the previous year was 47683 (All India Rank Open Category).

The cutoff ranks for the CSE branch in UIET KUK for JEE Main 2023 are: Round 1: 72021 - 259156

Considering these cutoff ranks, a rank of 110000 would not be competitive enough to secure admission in the CSE branch at UIET KUK.

New answer posted

2 years ago

0 Follower 6 Views

Y
Yatendra Kumar

Contributor-Level 10

According to GATE CCMT cutoff 2024, it is necessary to get more than 30 percentile (300 score out of 1000) in GATE entrance exams to get admission into one of the IIITs. For instance, IIIT Bhagalpur M.Tech cutoff 2024 has been released across multiple specialisations. Based on the Round 1 seat allotment, the M.Tech cutoff scores ranged between 371 and 491 for the General AII India category students. To get into M.Tech. in Electric Vehicle Technology, the candidates have to score a minimum of 371 which is more than 30 percentile. So, considering the round 1 cutoff, candidates seeking admission to IIIT Bhagalpur must secure over and abov

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New answer posted

2 years ago

0 Follower 18 Views

N
Neha Arora

Contributor-Level 10

The NIT Delhi GATE CCMT Cutoff has been released for Round 1. The most competitive course was M.Tech in Computer Science and Engineering. The Cutoff for M.Tech in CSE closed at 680 for the General AI category candidates. The least competitive course for the General AI category candidates was M.Tech. in Mechanical Engineering (CAD/CAM), with the closing Cutoff score of 396

For the OBC AI category candidates, the most competitive course was M.Tech in Computer Science and Engineering with a Cutoff score of 602. Candidates can check the NIT Delhi M.Tech Cutoff scores for different categories in the table provided in this section.&nbs

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New answer posted

2 years ago

0 Follower 4 Views

N
Neha Arora

Contributor-Level 10

The NIT Agartala GATE Cutoff 2024 has been released for Round 1. The Cutoff was released for various M.Tech courses for different categories. For the General AI category candidates, the Cutoff scores ranged between 350 and 528. The most competitive course was M.Tech in Artificial Intelligence, with the closing cutoff of 528. Therefore, candidate with a Cutoff of 500 cannot get M.Tech in AI at NIT Agartala. 

For the OBC AI category candidates, the Cutoff for M.Tech in AI closed at 443. Therefore candidates falling under the OBC AI category can consider taking M.Tech in AI with the given score. 

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