Ncert Solutions Chemistry Class 12th

$Xe{F}_2+P{F}_5\to {\left[XeF\right]}^{+}{\left[P{F}_6\right]}^{-}$

Haemoglobin is a positive colloid. Hence greater is the charge of anion, more effective will be the coagulation of haemoglobin.

$$ Correct order of coagulating power is $P{O}_4^{3-}>S{O}_4^{2-}>C{l}^{-}$

Electrophoresis : The migration of colloidal particles under the influence of an electric field is known as electrophoresis.

XeF2 : Hybrid orbital = sigma bond + L.P

= 2 + 3

= 5 = sp3d

Shape will be linear

$5C_2{O}_4^{2-}+2Mn{O}_4^{-}+16H^{+}\to 2M{n}^{+}+8H_{2}O+10C{O}_2$

5 moles of $C_2{O}_4^{2-}$ ${}_{}{}_{}^{}$ is needed to reduce 2 moles of $Mn{O}_4^{2-}$ ${}_{}^{}$

1 mole of $C_2{O}_4^{2-}$  is needed to reduce $\frac{2}{5}$  moles of $Mn{O}_4^{2-}$

In physisorption multimolecular layers are formed on solid surface.

Emulsion is a colloidal solution of liquid in liquid.

Acidic Nature :