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Ncert Solutions Chemistry Class 12th

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Ncert Solutions Chemistry Class 12th Class 12th

The coordination number of an atom in a body- centred cubic structure is___________.

[Assume that the lattice is made up of atoms]

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Vishal Baghel

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Coordination no. of an atom in BCC is 8.

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Ncert Solutions Chemistry Class 12th Class 12th

In Freundlich adsorption isotherm at moderate pressure, the extent of adsorption $(\frac{x}{m})$ is directly proportional to P^x. The value of x is:

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Vishal Baghel

Contributor-Level 10

Freundlich adsorption Isotherm

$(\frac{x}{m}) = k {(P)}^{\frac{1}{n}}$

At moderate pressure ; $\frac{x}{m}$ $\frac{}{}$ varies non-linearly with P.

So, $x = \frac{1}{n}$

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Ncert Solutions Chemistry Class 12th Hydrogen

Which of the following equation depicts the oxidizing nature of H₂O₂?

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Vishal Baghel

Contributor-Level 10

$l^{-} + H_{2} O_{2} + 2 H^{+} \to l_{2} + 2 H_{2} O$

(-1) oxidation (0)

Here, I is reducing agent

$∴ H_{2} O_{2}$ behaves like oxidizing agent

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Ncert Solutions Chemistry Class 12th Class 12th

Given below are two statements:

Statement I : CeO₂ can be used for oxidation of aldehydes and ketones.

Statement II : Aqueous solution of EuSO₄ is a strong reducing agent.

In the light of the above statements, choose the correct answer from the options given below:

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Vishal Baghel

Contributor-Level 10

In Ce & Eu (+3) oxidation state is more stable

$∴ C e^{+ 4} + e^{-} \to C e^{+ 3} (R e d u c t i o n)$ so CeO₂ is oxidising agent

$E u^{+ 2} \to E u^{+ 3} + e - (o x i d a t i o n)$ so EuSO₄ is reducing agent

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Ncert Solutions Chemistry Class 12th Class 12th

The major product of the following chemical reaction is:

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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Ncert Solutions Chemistry Class 12th Class 12th

Which one of the following reactions will not form acetaldehyde?

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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Ncert Solutions Chemistry Class 12th Class 12th

Match List – I with List – II

List – I List – II

...more

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Vishal Baghel

Contributor-Level 10

Aluminium - Kaolinite

Iron - Siderite

Copper - Malachite

Zinc &

...more

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Ncert Solutions Chemistry Class 12th Class 12th

Match List – I and List – II.

List – I List – II

...more

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Vishal Baghel

Contributor-Level 10

Valium – Tranquilizer

Morphine – Analgesic

Norethindrone – Antifertility drug

Vitamin B₁₂ – Pernicious anaemia

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Ncert Solutions Chemistry Class 12th Class 12th

Match List with List II.

List I List II

(Monomer Unit)

...more

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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Ncert Solutions Chemistry Class 12th Class 12th

In Freundlich adsorption isotherm, slope of AB line is:

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Vishal Baghel

Contributor-Level 10

Freundlich adsorption isotherm

$\frac{x}{m} = k p^{1 / n}$

$l o g \frac{x}{m} = \frac{1}{n} l o g p + l o g k$

Comparing with y = mx + C

so, slope of given graph is $\frac{1}{n}$ $\frac{}{}$ whose value varies from 0 to 1.

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