CSIR NET application process 2020 to end tomorrow; apply now

CSIR NET application process 2020 to end tomorrow; apply now

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New Delhi, Updated on May 14, 2020 10:26 IST
CSIR NET application form submission process will end tomorrow. Apply online for CSIR NET 2020 now.

CSIR NET application form submission process will end tomorrow. Apply online for CSIR NET 2020 now.

CSIR NET application to end tomorrow

The National Testing Agency (NTA) will end the CSIR NET application form 2020 submission process tomorrow, May 15. Interested candidates who have not yet filled the CSIR UGC NET application form can do the same on the official website of the exam. However, before applying for the exam, candidates must check the CSIR NET 2020 eligibility criteria.

Latest Updates: CSIR NET application process extended to May 31

Few days back, NTA had relaxed the document upload criteria for CSIR UGC NET aspirants. This means that candidates who are not able to obtain the required documents/certificates (such as result awaited attestation form or category certificate) owing to the lockdown imposed due to COVID-19 pandemic, can submit the CSIR NET 2020 online form without such documents.

Such candidates can upload an undertaking mentioning, “The updated and valid Category Certificate (SC/ST/OBC/EWS/PwD etc.)/Result Awaited Attestation Form/any other documents from competent authority shall be furnished as and when it is required by the CSIR.” It may, however, be noted that uploading of scanned images of photo and signature are still mandatory for candidates.       

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Interested and eligible candidates can fill the CSIR UGC NET application form on the official website (https://csirnet.nta.nic.in/webinfo/public/home.aspx) in two parts – registration and application. CSIR NET application fee for various category candidates is as mentioned below:

Category

CSIR NET Application Fee 2020 (in Rs)

General

1,000

OBC – Non-creamy layer

500

SC/ST

250

PwD

Nil

Know the step-by-step procedure of filling the CSIR NET application form 2020 here:

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