Magnetism and Matter

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New answer posted•a year ago
S
a year ago

Kindly consider the following answer

μ → = − e 2 m L →

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New answer posted•a year ago
S
a year ago

Let angle of dip =

Then B cos 45° = B’ cos 60°- (i)

B’ sin 60 = B sin - (ii)

( i ) ÷ ( i i ) ⇒ c o s t 6 0 = c o t α c o s 4 5 °

c o t α = c o t 6 0 ° c o s 4 5 ° = 1 2 3 x = 2 3

t a n α = 3 2

α = t a n − 1 3 2

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

D i m e n s i o n     o f     B 2 μ 0 : − Magnetic energy density

u B = B 2 2 μ 0

Dimension J m 3 → [ M L 2 T − 2 L − 3 ]

= [ M L − 1 T − 2 ]

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New answer posted•a year ago
S
a year ago

High permeability and low retentivity

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New answer posted•a year ago
S
a year ago

Given x1 = 1.22mm

 x2 = 1.23mm

x3 = 1.19mm

&   x4 = 1.20mm

xmean=x1+x2+x3+x44=1.22+1.19+1.204=1.21

|Δx1|=|xmean−x1|=|1.21−1.22|=0.01

|Δx2|=|xmean−x2|=|1.2|−|1.23|=0.02

|Δx3|=|xmean−x3|=|1.21−1.19|=0.02

|Δ4|=|xmean−x4|=|1.21−1.20|=0.01

(Δx)mean=0.01+0.02+0.02+0.014

=0.064

%error=Δxmeanxmean=0.064×1.21×100

=6004×121

=150121%

x = 150

 

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago