Ncert Solutions Maths class 12th

The given system of eqⁿ in matrix form is AK = B

= 5 x 28 -13 + 4 x (-9)

= 140 - 13 - 76

= 51 ≠ 0 .

The given system of eqⁿ are consistent

The given system of eqⁿ using matrix form can be written as AK = B

$=3\left(0-5\right)+1\left(0+3\right)-2\left(0-6\right)$

= -15 + 3 + 12

 = -15 + 15

= 0

The given system of eqⁿ using matrix method can be expressed as

                 AK = B

$=\left(6a-2a\right)-\left(4a-2a\right)+\left(2a-3a\right)$

= 4a – 2a – a

= a ≠ 0.

Hence, the given system of eqⁿ is consistent

The given system of equation can be written in the form AK = B

Hence the given system of eqⁿ are inconsistent.

The given system of eqⁿ can be written in the form AK = B where

Now, = 2 – (-1) = 2 + 1 = 3 ≠ 0.

∴ The system of eqⁿis consistent.

The given system of equation can be written in the form of AK = B

Now,  = 3 × 1 - 2 × 2 = 3 - 4 = -1 ≠ 0.

∴ The system has unique solⁿ  and hence equation are consistent

Given, A is an invertible matrix of order 2.

∴ Option (B) is correct.

Kindly go through the solution

Given, A= $\left[\begin{array}{cc}\hfill 1\hfill & \hfill 1\hfill \\ \hfill 1\hfill & \hfill 2\hfill & \hfill -3\hfill \\ \hfill 2\hfill & \hfill -1\hfill & \hfill 3\hfill \end{array}\right]$

Kindly go through the solution

⇒ b = 1