Physics

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New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

E = V R 2 + ( V L V C ) 2

E = ( 6 0 ) 2 + ( 1 0 0 2 0 ) 2

E = 100V

New answer posted

3 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

F = i l * B

? m g sin ? θ = i l * B

? m g sin ? θ = B cos ? θ l v R l B cos ? θ

? V = R m g sin ? θ B 2 l 2 cos 2 ? θ

 

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

1 f = 1 v 1 u

1 f = 1 1 0 0 1 5 0 = 1 5 0 1 1 0 0

f = + 1 0 0 c m

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

C e q = 2 C = 2 A ε 0 d

New answer posted

3 months ago

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R
Raj Pandey

Contributor-Level 9

a b = | a * b | a b  cos θ=ab sin θ

a b _ a b _ = s i n θ c o s θ

 tan θ=1

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

Inside a spherical shell gravitational field is zero, so net force acting on a particle placed inside it is also zero.

Total energy of a bound system is always negative.

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

Work done = Δ K E

f = x

f = x y

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

Time (minimum) taken to cross the river

t = W V s / r = 200 * 10 - 3 2

100 * 10 - 3 h

= 0.1 h = 6 m i n u t e s

New answer posted

3 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

(b)  L1=  Length of rod =20.123cm

L2=  Length of rod = 18.1cm

Difference in length  

= 20.123-18.1

 =2.0 cm

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