Ampere Circuital Law

The magnetic field at any point inside the pipe is zero

Using Ampere’s law for long hollow cylinder carrying current on its surface

B_in = 0

$B_{out}=\frac{{\mu }_{0}i}{2\pi r}$  

Gravitational constant $=\left. [{\mathrm{M}}^{-1}{\mathrm{L}}^3{\mathrm{T}}^{-2}\right]$

Gravitational potential energy $=\left. [{\mathrm{M}\mathrm{L}}^2{\mathrm{T}}^{-2}\right]$

Gravitational potential $=\left. [{\mathrm{L}}^2{\mathrm{T}}^{-2}\right]$

Gravitational intensity $=\left. [{\mathrm{L}\mathrm{T}}^{-2}\right]$