B.Tech Eligibility
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New answer posted
8 months agoContributor-Level 10
Candidates for the B.E./B.Tech programme at Sinhgad Institute of Technology and Science (SITS), Narhe, must complete their 10+2 coursework in mathematics, physics, and chemistry with an aggregate score of at least 45% (40 percent for reserved categories, Maharashtra State only). It is necessary to have a valid MHT CET or JEE Main score. Admission is done through DTE Maharashtra's Centralized Admission Process (CAP) with 20% going through management quota and 80% going through MHT CET. Through MHT CET Diploma holders with 50% of the possible points can apply for lateral admission.
New answer posted
8 months agoContributor-Level 10
Angel College of Engineering and Technology (ACET) requires candidates to have passed the 10+2 or equivalent exam with physics, chemistry and mathematics as core topics in order to be eligible for B.E./B.Tech programs. The minimum percentage of marks required by the Tamil Nadu government must also be met by them; this is normally approximately 45% for general categories and somewhat less for reserved categories. Typically the TNEA counseling process is used for admission. Additionally candidates must meet the age requirements and other rules set forth by the Directorate of Technical Education and Anna University.
New answer posted
8 months agoContributor-Level 10
Candidates must earn at least 50% of the possible points (45% for restricted categories) in Physics, Mathematics, and Chemistry/Biology in their 10+2 exam. They have to be eligible for Anna University's TNEA 2025 counseling. As an alternative, lateral admission is possible with a Diploma in Engineering or Technology with 45% of the possible points (or 40% for protected categories). Merit-based admission is determined by TNEA ranks.
New answer posted
8 months agoContributor-Level 10
In order to be considered, candidates must have completed their 10+2 coursework with physics and math as required courses and computer science, chemistry, biology, or biotechnology as electives. The qualifying exam requires a minimum aggregate score of 45% (or 40% for protected categories). WBJEE or JEE Main scores are used to determine admission. Candidates must have a B.Sc. in mathematics or a Diploma in engineering or technology from an accredited board or university in order to be considered for lateral admission It is required to have Indian citizenship or OCI status.
New answer posted
8 months agoContributor-Level 10
To study at TINT, you need to have completed Class 12 with Physics, Chemistry, and Mathematics, securing at least forty-five percent aggregate marks. Admission is based on West Bengal Joint Entrance Examination (WBJEE) score or merit in Class 12. There's also an institute-level quota for students who perform well academically or through state board results. TINT values both exam performance and consistent school results it looks for dedication to your field, not just test ranks.
New answer posted
8 months agoBeginner-Level 5
THE ELIGIBILITY FOR P.K CAMPUS
candidate needs to pass their 10th and 12th with physics and maths as compulsory subjects along with one of the following
chemistry biology technical vocational subject technology informative practice agriculture or engineering graphics a minimum of 45 percent aggregrate marks in these subjects is typically required
and admission is based on apllicant performance in JEE or MHTCET
New answer posted
8 months agoContributor-Level 10
To be eligible for NCT's B.E./B.Tech courses, you need to have completed Class 12 or equivalent with Physics, Chemistry, and Mathematics. A minimum of forty-five percent aggregate marks is typically required, with some relaxation for reserved categories. Admission is through TNEA for most programs, though there is a management quota as well. Strong academic performance in Science is the main criteria.
New answer posted
8 months agoContributor-Level 10
To study here, you need to have passed Class 12 with Physics, Chemistry, and Mathematics. A minimum aggregate of around forty-five to fifty percent in these subjects is the usual requirement. Admission is mostly through TNEA counselling, but the college also offers management quota spots. If you meet the marks and interest requirements, SREC welcomes you into a caring academic community where progress is encouraged every day.
New answer posted
8 months agoContributor-Level 8
To be eligible for admission to the BE/BTech course at Srinivasa Institute of Engineering and Technology, the candidate has to score a minimum of 45% aggregate in class 12 with Mathematics, Physics, and Chemistry as options from any recognised board. Eligible students will have to appear for the AP EAMCET exam and score valid marks to be eligible for the course.
New answer posted
8 months agoBeginner-Level 5
To be eligible for B.E. / B.Tech at Dr. D.Y. Patil College of Engineering and Innovation, a student must have passed 10+2 or equivalent with Physics, Mathematics, and Chemistry/Biology/Technical subject, securing at least 45% marks (40% for reserved categories). Additionally, a valid MHT CET or JEE Main score is required for admission through the centralized admission process .
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