Complement of a Set

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New answer posted•a year ago
R
a year ago

n ( A ∪ B ∪ C ) + n ( A ∪ B ∪ C ) ' = 50

n ( ∪ ) = 50

n ( A ∪ B ∪ C ) ' = n ( ∪ ) - n ( A ∪ B ∪ C ) ⇒ 50 - 29 ⇒ 21

n ( A ∪ B ∪ C ) = n ( A ) + n ( B ) + n ( C ) - n ( A ∩ B ) - n ( B ∩ C ) - n ( C ∩ A ) - n ( A ∩ B ∩ C )

⇒ 10 + 15 + 20 - 5 - 6 - 10 - 5 ⇒ 29

n ( A ∪ B ∪ C ) ' = 21

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