Complement of a Set

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R
Raj Pandey

Contributor-Level 9

n ( A B C ) + n ( A B C ) ' = 50

n ( ) = 50

n ( A B C ) ' = n ( ) - n ( A B C ) 50 - 29 21

n ( A B C ) = n ( A ) + n ( B ) + n ( C ) - n ( A B ) - n ( B C ) - n ( C A ) - n ( A B C )

10 + 15 + 20 - 5 - 6 - 10 - 5 29

n ( A B C ) ' = 21

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