Computer Science Engineering
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New answer posted
3 years ago
Contributor-Level 10
NIT Surathkal will releases 6-8 rounds of JEE Main cutoffs for admission to BTech in CSE. The cutoffs are released on a rolling basis, and the seats are filled on a first-come, first-served basis. The cutoffs are based on the following factors:
- The JEE Main score of the candidate
- The category of the candidate
- The number of seats available in the course
Candidates must visit the official website of entrance exam to read clear instructions on how to proceed with the counselling process, once the round is released.
New answer posted
3 years agoNew answer posted
3 years agoContributor-Level 7
B.Tech COMPUTER Science AND ENGINEERING
B.Tech COMPUTER Science & ENGINEERING (HONS. ). WITH specialisation IN ARTIFICIAL INTELLIGENCE & MACHINE LEARNING
B.Tech COMPUTER Science & ENGINEERING (HONS. ). WITH specialisation IN CLOUD COMPUTING
B.Tech COMPUTER Science & ENGINEERING (HONS. ). WITH specialisation IN BLOCKCHAIN
B.Tech COMPUTER Science & ENGINEERING (HONS. ). WITH specialisation IN CYBER SECURITY
1. Candidates must have passed 10+2 or equivalent from a recognised board with Physics Chemistry and Mathematics as compulsory
New answer posted
3 years agoBeginner-Level 5
New answer posted
3 years agoBeginner-Level 5
New answer posted
3 years agoContributor-Level 10
New answer posted
3 years agoContributor-Level 8
Grade percentage = (Grade earned / Total possible grade) x 100%
For example, if you earned a grade of B in a 3-credit course with a total possible grade of 100%, your grade percentage would be:
Grade percentage = (80 / 100) x 100% = 80%
Once you have calculated the grade percentage for each course, you can calcu
New answer posted
3 years agoBeginner-Level 5
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