Maths Spl
Get insights from 14.6k questions on Maths Spl, answered by students, alumni, and experts. You may also ask and answer any question you like about Maths Spl
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
9 years agoContributor-Level 7
New question posted
9 years agoNew question posted
9 years agoNew question posted
9 years agoNew answer posted
9 years ago
Guide-Level 15
New answer posted
9 years agoNew question posted
9 years agoNew answer posted
9 years agoBeginner-Level 2
tan13A-tan9A tan4A=tan13A tan9A tan4A
For this equation, we will use the formula:
I) tan 2a= tan(a + a) and,
II) tan (a + b)= (tan a+ tan b)/(1-tan a tan b)
From (I), we can say
tan 13A= tan (9A+4A)
but, tan(9A+4A)=(tan 9A + tan 4A)/ (1-tan 9Atan 4A)
Therefore tan13A=(tan 9A+tan4A)/(1-tan9Atan4A)
=tan13A-tan13Atan9Atan4A=tan 9A+tan 4A
Therefore,
tan13A-tan9A-tan4A=tan13A tan9A tan4A
New answer posted
9 years ago
Scholar-Level 16
Admission for all Bachelor degree program is open as of now you need to apply online and later on you will get the dates for admission process.
Further you can check at this link www.amity.edu/Mumbai .
All the best.
New answer posted
9 years ago
Scholar-Level 16
Now, the trend has changed and there are lots of options in arts and commerce stream. Check below mentioned options for your future reference:
Law
Psychology
International relations
Management
Economics Hons
ACCA certification
Company secretary
Journalism
Advertising
Event management
Digital marketing
You need to hunt for knowledge, not money. If you have knowledge and skills you will earn money.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 689k Reviews
- 1850k Answers
