Tags Motion in Magnetic Field

Motion in Magnetic Field

Get insights from 4 questions on Motion in Magnetic Field, answered by students, alumni, and experts. You may also ask and answer any question you like about Motion in Magnetic Field

Follow Ask Question

Questions

Discussions

Active Users

Followers

New answer posted

2 weeks ago

Motion in Magnetic Field Class 12th

A neutral point is obtained at the Centre of a vertical circular coil carrying current. The angle between the plane of the coil and the magnetic meridian is

0 Follower 2 Views

Raj Pandey

Contributor-Level 9

$θ = 90 °$

0 0

New answer posted

3 weeks ago

Motion in Magnetic Field Class 12th

Two ions of masses 4 amu and 16 amu have charges +2e and +3e respectively. These ions pass through the region of constant perpendicular magnetic field. The kinetic energy of both ions is same. Then:

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

$R = \frac{\sqrt[]{2 E m}}{B . q}$

$\Rightarrow R * \frac{\sqrt[]{m}}{q}$

$\Rightarrow \frac{R_{1}}{R_{2}} = \frac{\sqrt[]{4}}{2} * \frac{3}{\sqrt[]{16}} = \frac{3}{4}$

$\Rightarrow R_{2} = \frac{4 R_{1}}{3}$

$s i n θ = \frac{d}{R} \Rightarrow θ α \frac{1}{2} \Rightarrow θ_{2} < θ_{1}$

0 0

New answer posted

3 weeks ago

Motion in Magnetic Field Class 12th

A cell having N turns is would tightly in the form of a spiral with inner and outer radii 'a' and 'b' respectively. Find the magnetic field at centre, when a current I passes through coil:

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

Let us consider an elementary ring of radius r and thickness dr in which current is flowing.

So, No. of turns in this elementary ring

$d N = (\frac{N}{b - a}) d r$

$∴ {(d B)}_{a t c e n t r e} = \frac{μ_{0} l d N}{2 r}$

$B = \frac{μ_{0} l N}{2 (b - a)} l n \frac{b}{a}$

0 0

New answer posted

a month ago

Motion in Magnetic Field Class 12th

A charge particle is moving in uniform magnetic field $(2 \hat{i} + 3 \hat{j})$ T. If it has an acceleration of $(α \hat{i} - 4 \hat{j}) m / s^{2}$ , then the value of will be

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

$\vec{a} ⊥ \vec{B}$

$\Rightarrow \vec{a} . \vec{B} = 0$

$\Rightarrow (2 α - 12) = 0$

= 6

0 0

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
688k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Need guidance on career and education? Ask our experts

Your Question

Motion in Magnetic Field

Questions

Discussions

Active Users

Followers

All

Discussions

Unanswered Questions

Share Your College Life Experience