National Institute of Technology, Rourkela (NIT-RKL)

For the B.Tech in Food Process Engineering For Home state closing rank was .
for General 55521
General Female 51637
EWS 10523
EWS Female 15830
OBC NCL 20797
OBC NCL Female 39901
SC 10709
SC Female 15115
ST 3068
For Other state closing rank was.
for General 44270
General Female 58225
EWS 6724
OBC NCL 13629
OBC NCL Female 18418
SC 6198
SC Female 7469
ST 2210
Here, all ranks are in the respective catagory ranks

IIT Dhanbad Metallurgy.

In my opinion NIT Rourkela is one of the best colleges in the NIT branches. It has a lot of good placements.

First of all very congratulations for securing 132 marks. In 132 marks, your percentile will be around 96-97 and CRL will be around 35000-45000. Now if your home state is Odisha, then there is most probably chance that you can get there and infact with god branch, but if you are from other state, then there is little bit low chance from previous one but maximum possibility is that you can get seat there but in this case branch may be not of your choice.

Also with a category rank of around 8000, it will be hard for you to get a seat in any NITs IIITs and GFTIs for core branches such as CSE, ECE, etc. For that much rank you have to secure atleast 99+ and 97+ percentile score ( change depending upon exact conditions). .

Hi Malaya just go through this link and fill out the required details
College predictor in Shiksha
https://www.shiksha.com/college-predictor.

Just go through this link and fill out the required details:
https://www.shiksha.com/college-predictor

Student must score in the top 99th percentile to qualify into the computer science branch. It's just a straightforward mathematical computation here. 1 percentile indicates that 1 percent of the students scored higher than you. A percentile of 99 indicates that, out of the 10 lakh students who took the JEE Mains exam, about 10000 students scored higher than you. If we add up all the seats in all the NITs for this branch, there aren't as many left.

Hello Rahul Das, with percentile of about 60, you must appreciate that 40% out of roughly 10L meaning 4L students are above you. You first need to cross cutoff percentile of your catagory to be eligible for seeking admission in any NIT. NTA will do it in due course of time. Here is last year's cutoff for you to understand and appreciate.
2021 : Cut-off for JEE Advanced in different categories:-
General : 87.8992241
OBC NCL : 68.0234447
SC : 46.8825338
ST : 34.6728999
Gen EWS : 66.2214845
PwD : 0.0096375
Please do appear for second set of exams being conducted by NTA to improve your percentile.
Best wishes to you.

Hi.
NIT Rourkela is good for CSE branch.