NIT Surathkal - National Institute of Technology

Your Predicted Rank is 141064 JEE Main Percentile 83.86, AIR, ST.
Above is the possible rank you can get. The final rank will be based on the best of the scores of JEE-Mains January 2019 and April 2019 exam. The predicted rank may vary due to JEE Main tie breaker rules for same score. Kindly visit the following page for details on colleges open for the same. https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor.

At NIT Trichy, the ore and crores in last year for CS were 982 and 4041 and in Mechanical were 1053 and 10268 respectively. Hence, you have to score above 200 for CS and above 150 for mechanical. While at NIT Warangal or and crores in CS were 1435 and 1962 and or and crores in Mechanical were 5958 and 7966 respectively. Hence, you have to score above 200 for CS and above 150 for Mechanical in JEE Main.

Yes, I am 85 percent sure you'll be able to convert, rest depends on the GDPI.

SAT is accepted by the following Indian universities as well. The number of Indian universities accepting SAT scores from Indian students in India is increasing. The universities in India include
- Ashoka
- Manipal
- Azim Premji University
- Ahmedabad
- Bennett
- BML Munjal
-FLAME
- Manav Rachna
- SRM
- NMIMS
- GD Goenka
- Krea
- MS Ramaiah
- Shiv Nadar
- Srishti
- GITAM
- Sri Sri University
- World University of Design
etc.

Your Predicted Rank is 498180 JEE Main Percentile 43%, AIR, SC)
Above is the possible rank you can get. The final rank will be based on the best of the scores of JEE-Mains January 2019 and April 2019 exam. The predicted rank may vary due to JEE Main tie breaker rules for same score.
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor
Kindly visit the above link for the list of eligible colleges.

For foreign nationals/persons of Indian origin/ non-resident Indians/overseas citizen candidates:
Candidate must have passed 10+2 in relevant field with minimum 60% aggregate marks or 6.50 CGPA (on a 10 point scale) or equivalent in the qualifying examination form any recognized board.
Must have minimum 1440 score in SAT.
Must have born on or after October 01, 1991.
Final year appearing candidate can also apply on provisional basis.
Kindly note that the SAT score and cutoff ranks vary for different NITs.

NTA Scores are normalized scores across multi session papers and are based on the relative performance of all those who appeared for the examination in one session. The marks obtained are transformed into a scale ranging from 100 to 0 for each session of examinees.

Your predicted rank is 272863 JEE Main Percentile 68.78%, AIR, GEN)
Above is the possible rank you can get. The final rank will be based on the best of the scores of JEE-Mains January 2019 and April 2019 exam. The predicted rank may vary due to JEE Main tie breaker rules for same score.
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor
Kindly visit the above link for the list of eligible colleges.

The cutoffs are yet to be published, please check the official website for more information (https://www.nitk.ac.in/). .

Kindly visit the adjoining link, https://www.shiksha.com/college/national-institute-of-technology-surathkal-mangalore-24187?q=NIT+National+Institute+Of+Technology+Surathkal&rf=searchwidget&landing=ilp.