The cutoff for the B.Des course at IIT Delhi in 2025 (Round 1) was a closing rank of 35 for the General (AI) category. For other categories, the cutoff ranks were 21 for OBC and 11 for SC candidates. Admission is based on UCEED scores followed by a counselling process.
B.Des Cut-off
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New answer posted
11 months agoContributor-Level 10
The NIFT Bhubaneswar cutoff 2025 has been released up to multiple rounds, wherein the closing rank for B.Des. in Textile Design during Round 3 admission was 8741 for the students belonging to the General AI quota. For other categories, check out the table provided below:
| Category | NIFT Round 3 Cutoff 2025 |
|---|---|
| General | 8741 |
| OBC | 5063 |
| SC | 8741 |
| EWS | 7155 |
New answer posted
11 months agoContributor-Level 10
For the General AI category students, the NIFT Bangalore B.Des cutoff 2025 ranged between 253 and 802 during Round 2 admission. The cutoff ranks vary for different specializations, rounds and categories. So, if you are seeking admission based on the second cutoff list, yes, the chances are high that you will get a seat for B.Des at NIFT Bangalore with a cutoff rank of 800. Check out the table below to view the NIFT Round 2 cutoff ranks 2025 for the General AI category students.
| Course | NIFT Round 2 Cutoff 2025 |
|---|---|
| B.Des. in Accessory Design | 299 |
| B.Des. in Fashion Design | 253 |
| B.Des. in Knitwear Design | 802 |
New answer posted
12 months agoContributor-Level 10
NIFT Chennai cutoff 2025 has been released for different categories of students belonging to the General AI quota. Considering the Round 1 cutoff, the closing ranks for General AI category students varied between 130 and 1420. The most sought-after course for admission with the lowest cutoff rank of 130 was Master of Fashion Management (MFM). For other courses and specialisations, the cutoff ranks are tabulated below:
| Course | NIFT Round 1 Cutoff 2025 |
|---|---|
| B.Des. in Accessory Design | 551 |
| B.Des. in Textile Design | 972 |
| B.Des. in Knitwear Design | 1220 |
| B.FTech. in Apparel Production | 253 |
| Master of Fashion Management (MFM) | 130 |
| B.Des. in Fashion Design | 471 |
| B.Des. in Leather Design | 1420 |
| B.Des. in Fashion Communication | 299 |
New answer posted
a year agoContributor-Level 10
IIT Roorkee B.Des cutoff 2026 has been released for multiple rounds and categories. For the General AI category students, the maximum rank required in UCEED was 90 for admission to the B.Des course. To check out the category-wise break-up, refer to the table below:
| Category | UCEED Cutoff 2026 |
|---|---|
| General | 90 |
| OBC | 51 |
| SC | 24 |
| ST | 17 |
| EWS | 20 |
New answer posted
a year agoNew answer posted
a year agoContributor-Level 10
IIT Roorkee accepts the UCEED entrance exam scores, followed by its counselling process for admission to BDes courses. So, to get a seat at the IIT Roorkee B.Des course, candidates must have a valid score to be eligible for the counselling process. For the General AI category students, the maximum UCEED cutoff rank required for admission was 90.
New answer posted
a year agoContributor-Level 10
The NIFT Cutoff 2026 has been announced for Round 2 for different categories. During Round 2 cutoffs, the last ranks were 212 - 2430 where Master of Design (M.Des.) was found to be the most difficult course among all courses at National Institute of Fashion Technology, Kannur for the students of General AI category students. In order to take admission in the institute, the students have to score a valid score. For other categories of students, you can visit this page.
New answer posted
a year agoContributor-Level 10
According to the NIFT Jodhpur cut-off 2026 round two lies in the range from 245 to 1919. Therefore, those students who have a rank within 1919 can qualify for admission in NIFT. This is the cutoff range for the General AI category , other categories will have different cutoffs.
New answer posted
2 years agoContributor-Level 10
Yes, with a cutoff of 36, you can get into IIT Hyderabad for B.Des admission in Round 2 of the UCEED Seat Allotment process. The Round 2 closing rank for B.Des was 36 for OBC category students, so a cutoff of 36 should be sufficient for admission.
Candidates can refer to the table below to check out the round 1 and the round 2 B.Des cutoff 2024 for the OBC category candidates:
| Rounds | UCEED Cutoff Rank for OBC |
|---|---|
| 1 | 36 |
| 2 | 36 |
New answer posted
2 years ago
Contributor-Level 10
For the students belonging to the General AI quota, the IIT Bombay UCEED cutoff 2025 was 14 in the last round. The cutoff rank varies for different rounds and categories. Candidates can refer to the table below to view the category-wise UCEED cutoff 2025 for the last round.
| Categories | UCEED Last Round Cutoff 2025 |
|---|---|
| General | 14 |
| OBC | 13 |
| SC | 7 |
| ST | 5 |
| EWS | 4 |
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