B.Tech Cut-off

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New answer posted•a year ago
S
a year ago

If you just want to grab a seat in IIT Patna then your OBC rank has to be in 2800-3200 OBC NCL rank while General rank would be around 12000. If you want to get top branches like CSE, ECE, then you will have to be in Top 500 of your category rank.

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New answer posted•a year ago
S
a year ago

Yes, it is possible to get a seat at IIT Ropar with a rank of 10,000 in JEE Advanced. For candidates belonging to the General All India category, the last round cutoff ranks were between 3214 and 15356. Although at 10,000 rank, the choice of specialisation would be limited, candidate can get admissi

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New answer posted•a year ago
S
a year ago

IIT Roorkee BTech cutoff 2026 for the General AI category ranged from 582 for BTech CSE to 8735 for BTech Biosciences and Bioengineering. Candidates can check the table below to know the IIT Roorkee branch-wise cutoff 2026.

CourseIIT Roorkee BTech cutoff 2026 (Round 1)IIT Roorkee BTech cutoff 2026 (Last Round)
B.Tech. in Chemical Engineering49995572
B.Tech. in Civil Engineering71557765
B.Tech. in Electrical Engineering21632269
B.Tech. in Electronics and Communication Engineering15311541
B.Tech. in Computer Science and Engineering582587
B.Tech. in Mechanical Engineering39924453
B.Tech. in Metallurgical and Materials Engineering74147977
B.Tech. in Production and Industrial Engineering57605903
B.Tech. in Engineering Physics41814251
B.Tech. Biosciences and Bioengineering81318735
B.Tech. in Data Science and Artificial Intelligence825847
B.Tech. in Energy Engineering48075418

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New answer posted•a year ago
S
a year ago

You would need to attain a rank of at least 282 or lower to attain a seat in the CSE course. If you want admission to the Electrical Engineering branch, a rank of  874 or lower would be acceptable. The lower the rank, the better the chance of admission. 

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New answer posted•a year ago
S
a year ago

IIT Madras accepts JEE Advanced scores for admission to the BTech and Integrated BTech specialistions. The cutoff was released for different categories belonging to the All India quota. Candidates can find the range of round 1 cutoff ranks for different categories in the table below:

CategoryCutoff Range (Round 1)
General 159 - 9912
OBC82 - 4504
SC65 - 2707
ST29 - 1359
EWS41 - 1743
PWD4 - 170

 

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New answer posted•a year ago
S
a year ago

IIEST Shibpur JEE Main cutoff 2026 has been released for admission to the BArch and BTech specialisations. The cutoff was declared for round 1 for different categories belonging to the All India and Home State quota.

Among the General HS category candidates, the closing ranks varied between 594 

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New answer posted•a year ago
S
a year ago

IIT Indore CSE cutoff 2026 ranged from 1639 in the first round to 1676 in the last round for the General AI category. Hence, this category of candidates need to attain a rank of at least 1676. 

See the table below to know the overall cutoff range for other categories.

CategoryIIT Indore CSE cutoff 2026
General 1639 - 1676
OBC689 - 713
SC342 - 394
ST142 - 142 (R1)
EWS259 - 271
PWD68 - 68 (R1)

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New answer posted•a year ago
S
a year ago

Yes, you can get admission at this institution in the first round with a rank of 7k. The IIT Dharwad JEE Advanced cutoff 2026 ranged from 8332 to 18223 for the General AI category in round. You eligible for admission to the most competitive BTech branch (CSE). This course had the last round clo

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New answer posted•a year ago
S
a year ago

NMIT Bangalore cutoff 2026 has been released for Round 1 admission to the BTech course and its various specialisations. For the General AI category, the round 1 cutoff ranged from 12000 to 120000. Hence, students need to attain a rank of at least 120000 to be qualfied for admission. 

R

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New answer posted•a year ago
S
a year ago

Yes, you can gain admission at NMIT Bangalore with a cutoff of 4000 if you belong to the General AI category. With the attained rank, you might get admission at this institute but not to the most competitive branches, like BTech CSE or BTech AI and ML.

Students can check the table below to know which

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