Class 11th
Get insights from 8k questions on Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 11th
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
a month agoContributor-Level 10
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
New answer posted
a month agoContributor-Level 10
(1) [Ni (NH3)6]+2 → Ni+2 → d8, C. No. = 6,
SP3d2, Para
(2) [Co (H2O)6]+2 → Co+2 → d6, C. No. = 6
d2sp3, Dia
(3) [Ti (H2O)6]+3 → Ti+3 → d1, C. No. = 6
d2SP3, Para
(4) [Co (NH3)6]+3 → Co+3 → d5, C. No. = 6
d2sp3, Para
New answer posted
a month agoContributor-Level 10
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 678k Reviews
- 1800k Answers