Computer Science and Engineering

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2 years ago

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2 years ago

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T
tarun mittal

Contributor-Level 10

According to a source I found, to qualify for NITs, candidates in the General Category must score at least 95 percentile. NITs are available to reserved category candidates with an 80 percentile score or higher. For NIT, candidates must get at least 99.4 percentile on the JEE Main. For IIITs, the minimum rank required by the candidates for admission is known as the IIIT CSE cutoff. Like every year, the cutoff of the CSE programme offered by IIITs has been announced by the Joint Seat Allocation Authority JoSAA for round 6. Candidates can check the same below. I hope this helps! Let me know if you have any other questions.

New answer posted

2 years ago

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T
tarun mittal

Contributor-Level 10

According to a source I found, there is no minimum percentile required for CSE in Shri Guru Gobind Singhji Institute of Engineering and Technology (SGGSIE&T) Nanded. The main aspect is your rank on which the admission is given to all the aspirants. For any reputed government colleges your rank must be under 25000 (if you include your home state quota) to enroll in CSE. I hope this helps! Let me know if you have any other questions.

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2 years ago

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New answer posted

2 years ago

0 Follower 18 Views

T
tarun mittal

Contributor-Level 10

To calculate your rank from percentile score, you can use the formula (100 P)/100)*N + 1, where P denotes the NTA score and N denotes the number of students. Since you scored 97.92 percentile in JEE Main Feb 2021 and belong to EWS category, your EWS rank can be calculated using the above formula. However, I do not have the number of students who appeared for the exam in Feb 2021. You can use the formula to calculate your rank once you have that information. I hope this helps! Let me know if you have any other questions.

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2 years ago

0 Follower 138 Views

T
tarun mittal

Contributor-Level 10

The JEE Main cutoff for CSE at NIT Karnataka ranges from 578-1002 for the general category. However, it is important to note that the cutoff varies every year depending on various factors such as the number of students appearing for the exam, the difficulty level of the exam, and the number of seats available. 

New answer posted

2 years ago

0 Follower 688 Views

T
tarun mittal

Contributor-Level 10

According to the information I found, SASTRA University does not have a minimum percentile requirement for admission to CSE. It is based on 12th percentage and JEE Main mark (SASTRA will calculate like this 12th percentage * 0.75 + JEE Main mark * 0.25) Total 165 marks. And out of 165 marks what is your marks based on that they will give the seat.
I hope this helps! Let me know if you have any other questions.

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2 years ago

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2 years ago

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Shiksha Ask & Answer
Bhukya Sharath Naik

Contributor-Level 10

With 93 percentile in JEE Mains, it is not possible to get NITs or IITs for CSE branch because the cutoff for CSE branch goes very high, something 95 percentile above. I hope this helps! Let me know if you have any other questions.

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2 years ago

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Shiksha Ask & Answer
Bhukya Sharath Naik

Contributor-Level 10

Yes, you can get admission in B.Tech CSE and other branches as well without any entrance examination as there are colleges which offer admission based on class 12th marks. Sri Sivasubramaniya Nadar College of Engineering, Kalavakkam is one such college that offers admission in B.Tech on the basis of 12th marks. I hope this helps! Let me know if you have any other questions.

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