Engineering Entrance Exam

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New answer posted

7 months ago

0 Follower 13 Views

N
Nitesh Lama

Contributor-Level 7

As per the IIT Roorkee JEE Advanced cutoff 2024, the needed rank for DS and AI programme stood at 132 for the General AI category candidates. Further, candidates need to have valid JEE Advanced score to be eligible for the DS and AI course.

New answer posted

7 months ago

0 Follower 9 Views

N
Nishtha Kaur

Contributor-Level 7

The IIT Roorkee cutoff 2024 has been released for All India category candidates. For the General AI category, the BTech cutoff stood between 18 and 199 for the PWD AI quota. Similarly, for the EWS AI quota, the BTech cutoff stood between 90 and 2926. For both the quotas, the most competitive course was BTech in Computer Science and Engineering.

New answer posted

7 months ago

0 Follower 13 Views

P
Parul Jain

Contributor-Level 7

IIT Roorkee JEE Advanced 2025 Counselling: Steps to follow
Step 1: Registration: As the first step, candidates must register for JEE Advanced 2023 counselling and seat allotment. Students will need to use their JEE Main roll number and JEE Advanced password as credentials while logging in.
Step 2: Filling and Locking of Choice: After registration, candidates will have to select the college and courses of their choice from the available options and lock them.
Step 3: Allotment of Seats: The authorities will conduct mock seat allotments for candidates as per the choices they make. Candidates will be allowed to change their choices after mock allotment. Seats will be allotted to students as per their merit, preferred choices, category and availability.
Step 4: Reporting at Centres: After the allotment of seats, candidates will have to download their allotment letter and have to pay the seat acceptance fee. They will need to carry the requisite documents to the respective centres for verification.

New answer posted

7 months ago

0 Follower 5 Views

T
Tanisha Jain

Contributor-Level 7

IIT Roorkee accepts JEE Advanced scores. Candidates aiming for IIT Roorkee for BTech courses must have a score between 481 and 19885 for the General AI category candidates. Wherein, the courses having the most competitive ranks and least competitive ranks were BTech in CSE and Bachelor of Architecture (B.Arch.)  were 481 and 19885, respectively. For OBC AI category, the needed rank ranged between 421 and 6973.

New answer posted

7 months ago

0 Follower 3 Views

J
Jaiveer .

Beginner-Level 4

The fee structure for all BTech courses is are same, even if you are a CSE student or a biotechnology student, which is INR 2.36 lacs per annum.

 

New answer posted

7 months ago

0 Follower 4 Views

J
Jaiveer .

Beginner-Level 4

According to previous year trend you are eligible for all branches in DTU on this rank.

2024  DTUs CSE 5th round cut-off was 12590.

New answer posted

7 months ago

0 Follower 6 Views

P
Pallavi Pathak

Contributor-Level 10

The energy stored in a sytem of charges due to their positions in the electric field is called the electrostatic potential energy. The energy for the two charges q1 and q2 separated by distance r is:

The energy is positive if both charges are of the same sign and it is negative if for the opposite signs. When a system has over two charges, the energy is calculated by the sum of energies of all unique pairs. This concept helps analyze behaviour and stability of charged systems.

New answer posted

7 months ago

0 Follower 2 Views

P
Pallavi Pathak

Contributor-Level 10

When placed in an electric field, polarization is the alignment of dipole moments in a dielectric material. In a dielectric, molecules are randomly oriented. When an electric field is applied, it creates induced dipoles by slight shift in molecules from positive to negative. This weakend the net field, reduces the internal electric field and allow more charge storage. The polarization is quantified as:

Here, V is the volume, Pm is the total dipole moment. The polarization is a key concept in understanding the dielectric behavior in capacitors and it leads to increased capacitance.

New answer posted

7 months ago

0 Follower 5 Views

P
Pallavi Pathak

Contributor-Level 10

In an electric field, energy density is the amount of energy stored per unit volume . For a linera or vacuum dieletric, it is given by:

E is the electric field magnitude and ?0  is the permittivity of free space. 

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