Engineering

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New answer posted•3 years ago

How to obtain UPESEAT/UPES application form?

5 Views|Posted 3 years ago
Asked by Shikha Goyal
S
3 years ago

The application form for UPESEAT will be available online mode at the official website. The link to fill in the UPESEAT application form will also be updated on this page. The application process for UPESEAT comprises registration, filling forms, uploading documents, and payment of fees. Candidates

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New answer posted•3 years ago
S
3 years ago

Basically it depends upon how big is your pocket. Thapar provides you more exposure and higher placement package whereas GNDU also has good placements but with lower package. Both are good. In the end if you are having good score in JEE and you can afford expenses of Thapar university(1 lakh+ for on

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New answer posted•3 years ago
S
3 years ago

The cutoff trend for BTech at IIIT Delhi has been decreasing in the recent years. In 2024, the closing rank for BTech under general category for all India quota was 10559. In 2023, it improved to 8670. Similar cut off trend can be seen for female candidates under all categories however the ranks are

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New answer posted•3 years ago
S
3 years ago

Opening and Closing rank depends on the category and quota of candidates. For the General category under All India, opening rank was 4554 and closing rank was 4659 in 2023. The cutoff in 2024 for the all-India quota ranged from 6695 to 9975. Cut off are differant when it comes to other categories or

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New answer posted•3 years ago
S
3 years ago

In 2024, the cutoff ranks for BTech in Computer Science and Applied Mathematics at IIIT Delhi other than General category was - 23566 for OBC, 94128 for SC, 103550 for ST, and 13240 for EWS. While the admissions are based on the scores/rank obtained in JEE exam, the last cut offs also change a lot d

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New answer posted•3 years ago
S
3 years ago

As per the IIT Delhi cutoff 2022 for round 1 seat allocation, the closing cutoff ranks for BTech courses fall between 101 and 11244. BTech chemical engineering admission in IITs taken place through JEE Advanced followed by JoSAA Counseling. Student must secure a rank between 10,000 -13,000 in JEE Ad

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New answer posted•3 years ago
Lalit Bhandari
3 years ago

For last year, the closing rank for B.Tech in Computer Science and Engineering was 102 which is very far off from the following range. This was for General category under All India quota. Unless the candidate belongs to some other category or domicile, one cannot afford to score less than this. With

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New answer posted•3 years ago
Lalit Bhandari
3 years ago

Opening and closing rank depends on category & quota of candidates. For general category under All India, opening rank was 123 and the closing rank was 128 as per IIT Delhi JEE Advance cutoff 2026. Cut off are different when it comes to other categories or female candidates and even domicile of home

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New answer posted•3 years ago
Lalit Bhandari
3 years ago

For 2024, cut off was 4849 for General category candidates in All India quota for B.Tech. in Biochemical Engineering and Biotechnology in Indian Institute of Technology, Delhi. IIT Delhi B.Tech cut off varies depending on the category and domicile/quota of the applicant.

 

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New answer posted•3 years ago
S
3 years ago

The cutoff ranks for BTech in Electrical and Electronics Engineering 2022 at NIT Warangal other than General category was - 16530 for OBC, 1430 for SC, 590 for ST, 14856 for EWS, and 266 for PWD. While the admissions are based on the scores/rank obtained in JEE exam, the last cut offs also change

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