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New answer posted•a year ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

The locus of a point for which $x = 0$  is

(a) $x y$  -plane

(b) $y z$ -plane

(c) $z x$  -plane

(d) None of these

2 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} O n t h e y z p l a n e, x = 0 \\ H e n c e, t h e l o c u s o f t h e point i s y z p l a n e . \\ H e n c e, t h e c o r r e c t o p t i o n i s (b) . \end{array}$

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New answer posted•a year ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

The locus of a point for which $y = 0, z = 0$  is

(a) Equation of x-axis

(b) Equation of y-axis

(c) Equation of z-axis

(d) None of these

4 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} W e k n o w t h a t o n e e q u a t i o n o f x a x i s, y = 0, z = 0 \\ H e n c e, t h e l o c u s o f t h e point i s e q u a t i o n o f x a x i s . \\ H e n c e, t h e c o r r e c t o p t i o n i s (a) . \end{array}$

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New question posted•a year ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

The locus of a point for which <math> <mrow> <mi>y</mi> <mo>=</mo> <mn>0</mn> <mo>,</mo> <mi>z</mi> <mo>=</mo> <mn>0</mn> </mrow> </math>  is (a) Equation of <math> <mrow> <mi>x</mi> </mrow> </math> -axis (b) Equation of <math> <mrow> <mi>y</mi> </mrow> </math> -axis (c) Equation of <math> <mrow> <mi>z</mi> </mrow> </math> -axis (d) None of these

3 Views|Posted a year ago

Asked by Payal Gupta

New answer posted•a year ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

A plane is parallel to yz-plane so it is perpendicular to:

(a) x -axis

(b) y-axis

(c) z-axis

(d) None of these

2 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} A n y p l a n e p a r a l l e l t o y z - p l a n e i s p e r p e n d i c u l a r t o x - a x i s . \\ H e n c e, t h e c o r r e c t o p t i o n i s (a) . \end{array}$

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New question posted•a year ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

A plane is parallel to yz-plane so it is perpendicular to: (a) x  -axis (b) y -axis (c) z -axis (d) None of these

1 Views|Posted a year ago

Asked by Payal Gupta

New question posted•a year ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

A plane is parallel to <math> <mrow> <mi>y</mi> <mi>z</mi> </mrow> </math> -plane so it is perpendicular to: (a) <math> <mrow> <mi>x</mi> </mrow> </math>  -axis (b) <math> <mrow> <mi>y</mi> </mrow> </math>   -axis (c) <math> <mrow> <mi>z</mi> </mrow> </math>   -axis (d) None of these

1 Views|Posted a year ago

Asked by Payal Gupta

New answer posted•a year ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

The point $(2, 3, 4)$ lies in the

(a) First octant

(b) Seventh octant

(c) Second octant

(d) Eighth octant

4 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} T h e point (- 2, - 3, - 4) l i e s i n s e v e n t h octant . \\ H e n c e, t h e c o r r e c t o p t i o n i s (b) . \end{array}$

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New answer posted•a year ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

Equation of $y$ -axis is considered as

(a) $x = 0, y = 0$  

(b) $y = 0, z = 0$  

(c)  

(d) None of these

3 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} O n y - a x i s, x = 0 a n d z = 0 \\ H e n c e, t h e c o r r e c t o p t i o n i s (c) . \end{array}$

Upvote

New answer posted•a year ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

$x$ -axis is the intersection of two planes

(a) $x y$ and $x z$

(b) $y z$ and $z x$

(c) $x y$ and $y z$

(d) None of these

6 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} W e k n o w t h a t o n t h e x y a n d x z p l a n e s, t h e l i n e o f intersection i s x a x i s . \\ H e n c e, t h e c o r r e c t o p t i o n i s (a) . \end{array}$

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New answer posted•a year ago

Exemplar Solution Maths NCERT Exemplar Solutions Class 11th Chapter Twelve

If the distance between the points $(a, 0, 1)$ and $(0, 1, 2)$ is $\sqrt[]{27}$ , then the value of $a$ is

(a) 5

(b) $\pm 5$

(c) –5

(d) None of these

2 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} L e t t h e g i v e n points b e A (a, 0, 1) a n d B (0, 1, 2) \\ ∴ A B = \sqrt[]{{(a - 0)}^{2} + {(0 - 1)}^{2} + {(1 - 2)}^{2}} \\ \sqrt[]{27} = \sqrt[]{a^{2} + 1 + 1} \\ S q u a r i n g b o t h s i d e s, w e g e t \\ 27 = a^{2} + 2 \Rightarrow a^{2} = 25 ∴ a = \pm 5 \\ H e n c e, t h e c o r r e c t o p t i o n i s (b) . \end{array}$

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