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New question posted•a year ago

What are some government veterinary colleges I can expect at 90000 rank in NEET?

4 Views|1 Followers|Posted a year ago
Asked by Nayansh Deep
New question posted•a year ago
New question posted•a year ago
New question posted•a year ago
New question posted•a year ago
New answer posted•a year ago
S
a year ago

Explanation- velocity of a freely falling body is v= 2gh

And ? =hmv=hm2gh

? =h -1

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New answer posted•a year ago
S
a year ago

Explanation-number of photon emitted per second n= phc?=p?hc=20×5000×10-106.62×10-34×3×108

=5×1019s-1

(ii) E=hc /? = 6.62×10-34×3×1085000×10-10×1.6×10-19=2.48eV  this enegy is greater than 2 so emission is possible

(iii) work function ? = p4?d2×?r2?t = ?o

?t = 4?d2pr2 = 4×2×16×1.6×10-19×2220×(1.5×10-10)-2=28.4s

(iv) N= n?r24?d2×?t

 = 5×1019×(1.5×10-10)2×28.44×(2)2 =2

(v) as the time of emission is 11.04s so

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New answer posted•a year ago
S
a year ago

Explanation- according to law of conservation of momentum

S0 mAv+mb0=mAv1+mBv2

So mA(v-v1)= mBv2

according to law of conservation of kinetic energy

1/2mAv2=1/2mAv12+1/2mBv22

So mA(v2-v12)= mBv22

From above eqn we can say that v+v1=v2 or v=v2-v1

So v1= mA-mBmA+mB v  and v2= 2mAmA+mB v

? 

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New answer posted•a year ago
S
a year ago

Explanation -Given threshold frequency of A is given by v0A= 5 ×1014 hz

VOB= 10 × 1014hz

?=hv0

?OA?OB=5×101410×10141

?OA < ?OB

(ii)  for metal A slope=h/e= 2(10-5)1014

h=2e5×1014=2×1.6×10-195×1014 = 6.4 ×10-34 js

formetalB slope=h/e= 2.5(15-10)1014 = 8 ×10-34 js

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New answer posted•a year ago