Medicine

Explanation- A= 10^-4m²

So d= 10^-3 and i= 100^-4A

I= 100W/m²

$\mathrm{?}=600\mathrm{n}\mathrm{m}=600\times {10}^{-9}$

${\mathrm{?}}_{\mathrm{N}\mathrm{a}}=0.97\mathrm{k}\mathrm{g}/{\mathrm{m}}^3$

$\mathrm{v}\mathrm{o}\mathrm{l}\mathrm{u}\mathrm{m}\mathrm{e}=\mathrm{A}\times \mathrm{d}$ 10^-4(10^-3)=10^-7m³

$\mathrm{f}\mathrm{o}\mathrm{r}\mathrm{}23\mathrm{k}\mathrm{g}\mathrm{}\mathrm{o}\mathrm{f}\mathrm{}\mathrm{s}\mathrm{o}\mathrm{i}\mathrm{d}\mathrm{u}\mathrm{m}$

So volume Na atoms=23/0.97m³

Volume occupied by one Na atom= $\frac{23}{0.97\times 6\times {10}^{26}}=3.95\times {10}^{-26}{\mathrm{m}}^3$

Number of Na atoms in target $\frac{{10}^{-7}}{3.95\times {10}^{-26}}=2.53\times {10}^{18}$

So energy falling per sec= $\frac{\mathrm{n}\mathrm{h}\mathrm{c}}{\mathrm{?}}=\mathrm{I}\mathrm{A}$

So n= $\frac{\mathrm{I}\mathrm{A}\mathrm{?}}{\mathrm{h}\mathrm{c}}$ = $\frac{100\times {10}^{-4}\times 660\times {10}^{-9}}{6.62\times {10}^{-34}\times 3\times {10}^8}=3.3\times {10}^{16}$

N=P $\times \mathrm{n}\times \mathrm{N}\mathrm{a}=\mathrm{P}\times 3.3\times {10}^{16}\times 2.53\times {10}^{18}$

I = 100 $\times {10}^{-6}={10}^{-4}$ A

I=Ne= $\mathrm{P}\times 3.3\times {10}^{16}\times 2.53\times {10}^{18}$ ( ${10}^{-4}$&nb

BSEB 12th books are based on NCERT patterns, especially for Science subjects. These books help in building strong basics which are useful for exams like NEET, JEE, and other entrance tests. Subjects like Physics, Chemistry, and Biology in BSEB books explain core concepts clearly. After reading the t

Yes, MBBS coarse started in 2018 with annual intake of 50 and from 2020 annual intake increased to 125 and is continuing with the same annually, admission is via NEET UG exam.

MBBS coarse started in 2018 with annual intake of 50, from 2020 annual intake increased to 125, so currently annual intake in MBBS coarse is 125.