MHTCET Cut-off
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New answer posted
3 weeks agoContributor-Level 10
Yes, you can get into Mumbai University's affiliated colleges with a 50 percentile in the MHT CET exam if you belong to the General HS category. For this category, the Round 1 cutoff ranged from 38.67 to 99.1 for the BTech CSE course. Hence, getting admission with the attained percentile can be possible. Students can check the table below to know which colleges might accept their attained percentile.
Please note that the cutoff will vary for different categories, rounds, branches, etc.
| College | Mumbai University BE cutoff 2026 (Round 1) |
|---|---|
| Terna Engineering College, Osmanabad | 38.67 |
| Rajendra Mane College of Engineering and Technology (RMCET) | 43 |
| Metropolitan Institute of Technology and Management, Sindhudurg | 46.42 |
New answer posted
3 weeks agoContributor-Level 10
Mumbai University MHT CET cutoff 2026 has been released for admission to the BE course and its various branches. For the General AI category, the Round 1 cutoff for the BTech CSE course varied between 29.17 and 72.53.
For the OBC HS category, the same round and branch cutoff vaired from 7.64 to 94.19. Check the table below for Round 1 cutoff range for the BTech CSE course for various categories.
| Category (Home State quota) | Mumbai University MHT CET cutoff 2026 |
|---|---|
| General | 38.67 - 99.1 |
| OBC | 7.64 - 94.19 |
| SC | 27.88 - 93.13 |
New answer posted
a month agoContributor-Level 10
Yes, you can get into MIT-WPU Pune if you belong to any of the category under the All India quota. For the General AI category, the round 1 cutoff for the UG-level Engineering course is 96.8. Since, your score is 5000, you can easily get admission to this course at MIT-WPU Pune in the first round.
Check the list below to know the Round 1 score for all other All India categories.
- General: 96.8
- OBC: 93
- SC: 86.5
- ST: 80.5
- EWS: 96.8
- PWD: 96.8
New answer posted
a month agoContributor-Level 10
MIT WPU, Pune MHT CET cutoff 2026 was released for Round 1 admission to the BTech course and its various specialisations. For the General AI category, the Round 1 cutoff score is 96.8. Students can check the table below to know the Round 1 cutoff score of all other categories under the AI quota.
| Category | MIT WPU, Pune MHT CET cutoff 2026 |
|---|---|
| General | 96.8 |
| OBC | 93 |
| SC | 86.5 |
| ST | 80.5 |
| PWD | 96.8 |
| EWS | 96.8 |
Other rounds, categories will have different cutoffs.
New answer posted
a month ago
Beginner-Level 5
The marks required in MHT CET depend on the college, category, and exam difficulty. Based on recent admission trends, these are good target scores:
Branch
Approx. MHT CET Marks (out of 200)
Expected Percentile
Computer Science Engineering (CSE)
145–165+
99–99.7+
Artificial Intelligence (AI/AIML)
140–160+
98.5–99.5+
Mechanical Engineering
100–130+
92–97.5
For the top Maharashtra engineering colleges such as VJTI, COEP, and SPIT:
CSE: Aim for 99.5+ percentile (roughly 160+ marks in many exam shifts).
AI/AIML: Aim for 99+ percentile (around 145–160 marks).
Mechanical: Around 97–99 percentile is often competitive, depending on the college
New answer posted
2 months agoContributor-Level 10
Students who belong to the General AI category need to attain an MHT CET rank of at least 30491 if they want admission at this college to the BTech course branches. The DJ Sanghvi BTech cutoff 2025 ranged from 1584 to 30491 for the aforementioned category.
Students can check the table below to know the last round cutoff ranks for different engineering branches. Please know that other categories, rounds, quotas, etc., will have different cutoffs.
| Course | DJ Sanghvi BTech cutoff 2025 |
|---|---|
| BTech in Artificial Intelligence and Data Science | 4617 |
| BTech in Artificial Intelligence and Machine Learning | 6570 |
| BTech in Computer Engineering | 7176 |
| BTech in Computer Engineering (Data Science) | 7608 |
| BTech in Computer Engineering (Internet of Things and Cyber Security) | 7793 |
| BTech in Electronics and Telecommunication Engineering | 9167 |
| BTech in Information Technology | 18390 |
| BTech in Mechanical Engineering | 30491 |
New answer posted
2 months agoContributor-Level 10
For the General AI category, the DJ Sanghvi MHT CET cutoff 2025 ranged from 1584 in the first round to 30491 in the last round. Hence, General AI quota categories need to attain a rank of at least 30491 to be considered eligible for admission.
The DJ Sanghvi BTech cutoff 2025 was released for all rounds for admission to the BTech course and its various specialisations. The cutoff was in the form of ranks. Students can check the table below to know the round 1 and last round closing ranks for the aforementioned category.
| Course | Round 1 (Closing Rank) | Last Round (Closing Rank) |
|---|---|---|
| BTech in Computer Engineering | 1584 | 7176 |
| BTech in Information Technology | 2436 | 18390 |
| BTech in Artificial Intelligence and Data Science | 2558 | 4617 |
| BTech in Computer Engineering (Data Science) | 3017 | 7608 |
| BTech in Artificial Intelligence and Machine Learning | 3094 | 6570 |
| BTech in Computer Engineering (Internet of Things and Cyber Security) | 3246 | 7793 |
| BTech in Electronics and Telecommunication Engineering | 4404 | 9167 |
| BTech in Mechanical Engineering | 7451 | 30491 |
Other categories, rounds, etc., will have different cutoffs.
New answer posted
2 months agoContributor-Level 10
For the General AI category, the DJ Sanghvi MHT CET cutoff 2025 ranged from 1584 in the first round to 30491 in the last round. Hence, General AI quota categories need to attain a rank of at least 30491 to be considered eligible for admission.
The DJ Sanghvi BTech cutoff 2025 was released for all rounds for admission to the BTech course and its various specialisations. The cutoff was in the form of ranks. Students can check the table below to know the round 1 and last round closing ranks for the aforementioned category.
| Course | Round 1 (Closing Rank) | Last Round (Closing Rank) |
|---|---|---|
| BTech in Computer Engineering | 1584 | 7176 |
| BTech in Information Technology | 2436 | 18390 |
| BTech in Artificial Intelligence and Data Science | 2558 | 4617 |
| BTech in Computer Engineering (Data Science) | 3017 | 7608 |
| BTech in Artificial Intelligence and Machine Learning | 3094 | 6570 |
| BTech in Computer Engineering (Internet of Things and Cyber Security) | 3246 | 7793 |
| BTech in Electronics and Telecommunication Engineering | 4404 | 9167 |
| BTech in Mechanical Engineering | 7451 | 30491 |
Other categories, rounds, etc., will have different cutoffs.
New answer posted
a year agoContributor-Level 7
DY Patil Akurdi MHT CET M.Tech cutoff 2024 was concluded for admission to ME/MTech specialisations. The cutoff was released in the form of percentile, for different categories under the Home State quota. For the General Home State category candidates, the cutoff ranks were between 10 and 19.58, in the last round. Checkout the table below to find the cutoff percentile for various specialisations among the General HS category:
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New answer posted
2 years agoContributor-Level 10
Admission to Jawaharlal Darda Institute of Engineering and Technology is conducted through MHTCET scores. Based on the scores, the Jawaharlal Darda Institute of Engineering and Technology cutoff 2024 is released for the candidates. As per the cutoff released, getting a percentile of more than 48 is crucial to get an admission. Candidates must score the minimum score to qualify for the MHTCET exam and get eligible for admission.
The minimum marks to get eligible for the Jawaharlal Darda Institute of Engineering and Technology is 48.87 (B.E. in Mechanical Engineering) for the General Home State category candidates. Anybody who scores
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