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New question posted

a month ago

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New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a month ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a month ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

M = ∫ ρdV
M = ∫? (k/r) 4πr²dr
M = 4πkR?²/2 = 2πkR?²
F? = GMm/R?² = 2ω?²R

 

New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

v_max/v_min = (1+e)/ (1-e)
r_max/r_min = (1+e)/ (1-e) = 6

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

g_e = g - Rω²
g? = g - (2gh/R)


Now Rω² = 2gh/R
h = R²ω²/2g

New question posted

a month ago

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New answer posted

a month ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

90.5 J

- G M e M R + 1 2 M u 2 = - G M e M 2 R + 1 2 M v 2

  v = u 2 - G M e R Transverse velocity of rocket

V T  Radial velocity of rocket

V R

V - G M e 2 R

Kinetic energy M 10 V T = 9 M 10 G M e 2 R ; M 10 V r = M u 2 - G M e R

= 1 2 M 10 V T 2 + V r 2 = M 20 81 G M e 2 R + 100 u 2 - 100 G M e R

= M 20 100 u 2 - 119 G M 2 R

 

 

New answer posted

a month ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

W equator   = W pole   - m ω 2 R

= 196 - 19.6 * 2 π 24 * 60 * 60 2 * 6400 * 10 3 = 195.33 N

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