The P Block Elements
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In the following questions two or more options may be correct.
16. The reason for small radius of Ga compared to Al is
(A) Poor screening effect of d and f orbitals
(B) Increase in nuclear charge
(C) Presence of higher orbitals
(D) Higher atomic numbeR
In the following questions two or more options may be correct.
16. The reason for small radius of Ga compared to Al is
(A) Poor screening effect of d and f orbitals
(B) Increase in nuclear charge
(C) Presence of higher orbitals
(D) Higher atomic numbeR
This is a Multiple Choice Questions as classified in NCERT Exemplar
(A) & (B)
The atomic radii decrease as one moves down the group from Al to Ga due to the shielding effect of electrons. As a result of this ineffective effect, the effective nuclear charge rises.
Upvote 
Cement, the important building material is a mixture of oxides of several elements. Besides calcium, iron and sulfur, oxides of elements of which of the group(s) are present in the mixture?
(A) Group 2
(B) Groups 2,13 and 14
(C) Groups 2 and 13
(D) Groups 2 and 14
Cement, the important building material is a mixture of oxides of several elements. Besides calcium, iron and sulfur, oxides of elements of which of the group(s) are present in the mixture?
(A) Group 2
(B) Groups 2,13 and 14
(C) Groups 2 and 13
(D) Groups 2 and 14
This is a Multiple Choice Questions as classified in NCERT Exemplar
B
Cement is made by combining lime ( CaO ), clay with silica ( SiO), and oxides of aluminum, magnesium, and iron.
Upvote Dry ice is
(A) Solid NH3
(B) Solid SO2
(C) Solid CO2
(D) Solid N 2
Dry ice is
(A) Solid NH3
(B) Solid SO2
(C) Solid CO2
(D) Solid N 2
This is a Multiple Choice Questions as classified in NCERT Exemplar
C
Explanation:
Solid CO2 is referred to as dry ice because it is used in laboratories to create an ice bath for organic reactions. It is made by rapidly cooling high-pressure CO2 gas.
Upvote The most commonly used reducing agent is
(A) AlCl3
(B) PbCl2
(C) SnCl4
(D) SnCl2
The most commonly used reducing agent is
(A) AlCl3
(B) PbCl2
(C) SnCl4
(D) SnCl2
This is a Multiple Choice Questions as classified in NCERT Exemplar
D
Reducing agent are compound that donates electron to an electron recipient compound. Reducing agents oxidize themselves and reduce the other compounds. They easily lose electrons and increase their oxidation state; those electrons a
Upvote Quartz is extensively used as a piezoelectric material, it contains
(A) Pb
(B) Si
(C) Ti
(D) Sn
Quartz is extensively used as a piezoelectric material, it contains
(A) Pb
(B) Si
(C) Ti
(D) Sn
This is a Multiple Choice Questions as classified in NCERT Exemplar
B
Quartz is a crystalline form of silica that can be converted into other crystalline forms at high temperatures. It's commonly used as a piezoelectric material.
Upvote A compound X, of boron reacts with NH3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF3 with lithium aluminium hydride. The compounds X and Y are represented by the formulas.
(A) B2H6, B3 N3H6
(B) B203, B3 N3H6
(C) BF3, B3 N3H6
(D) B3 N3H6, B2H6
A compound X, of boron reacts with NH3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF3 with lithium aluminium hydride. The compounds X and Y are represented by the formulas.
(A) B2H6, B3 N3H6
(B) B203, B3 N3H6
(C) BF3, B3 N3H6
(D) B3 N3H6, B2H6
This is a Multiple Choice Questions as classified in NCERT Exemplar
A
A compound X, of boron, reacts with NH3 on heating to give another compound Y which is called inorganic benzene.
3H2H6 x + 6NH3 → 3 [BH2 (NH3)2]+ [BH4]− &n
Upvote In the structure of Diborane
(A) aAll hydrogen atoms lie in one plane and boron atoms lie in a plane perpendicular to this plane.
(B) 2 Boron atoms and 4 terminal hydrogen atoms lie in the same plane and 2 bridging hydrogen atoms lie in the perpendicular plane.
(C) 4 Bridging hydrogen atoms and boron atoms lie in one plane and two terminal hydrogen atoms lie in a plane perpendicular to this plane.
(D) All the atoms are in the same plane.
In the structure of Diborane
(A) aAll hydrogen atoms lie in one plane and boron atoms lie in a plane perpendicular to this plane.
(B) 2 Boron atoms and 4 terminal hydrogen atoms lie in the same plane and 2 bridging hydrogen atoms lie in the perpendicular plane.
(C) 4 Bridging hydrogen atoms and boron atoms lie in one plane and two terminal hydrogen atoms lie in a plane perpendicular to this plane.
(D) All the atoms are in the same plane.
This is a Multiple Choice Questions as classified in NCERT Exemplar
B
The four terminal hydrogen atoms and two boron atoms are all in the same plane.
There are two bridging hydrogen atoms above and below this plane.
The four terminal B-H bonds are regular two-centre-two-electron bonds, whereas the two b
Upvote Ionisation enthalpy (ΔtH1 kJ mol−1) for the elements of Group 13 follows the order.
(A) B>Al>Ga>In>Tl
(B) B<al<ga<in<tl< p=""> </al<ga<in<tl<>
(C) BGa<in<tl< p=""></in<tl<>
(D) B>A1In<tl< td=""> </tl<>
Ionisation enthalpy (ΔtH1 kJ mol−1) for the elements of Group 13 follows the order.
(A) B>Al>Ga>In>Tl
(B) B<al<ga<in<tl< p=""> </al<ga<in<tl<>
(C) BGa<in<tl< p=""></in<tl<>
(D) B>A1In<tl< td=""> </tl<>
This is a Multiple Choice Questions as classified in NCERT Exemplar
D
In group 13, the standardised trend of decrease of ionization enthalpy is not monitored.
As we move from Boron to Aluminium the atomic size increases and jonjation enthalpy decreases but when we move ahead from Aluminum to Gallium, t
Upvote Silicon has a strong tendency to form polymers like silicones. The chain length of silicone polymer can be controlled by adding
(A) MeSiCl3
(B) Me2SiCl2
(C) Me3SiCl
(D) Me4Si
Silicon has a strong tendency to form polymers like silicones. The chain length of silicone polymer can be controlled by adding
(A) MeSiCl3
(B) Me2SiCl2
(C) Me3SiCl
(D) Me4Si
This is a Multiple Choice Questions as classified in NCERT Exemplar
C
Me3SiCl is a soleuless liquid That has a major application in the formation of silicones. On its addition in the process, it blocks the end and controls the chain length of the polymer.
Upvote Catenation, i.e. linking of similar atoms depends on size and electronic configuration of atoms. The tendency of catenation in Group 14 elements follows the order
(A) C>Si>Ge>Sn
(B) C>>Si>Ge≈Sn
(C) Si>C>Sn>Ge
(D) Ge>Sn>Si>C
Catenation, i.e. linking of similar atoms depends on size and electronic configuration of atoms. The tendency of catenation in Group 14 elements follows the order
(A) C>Si>Ge>Sn
(B) C>>Si>Ge≈Sn
(C) Si>C>Sn>Ge
(D) Ge>Sn>Si>C
This is a Multiple Choice Questions as classified in NCERT Exemplar
B
In group 14, as we move down from C to Sn, the size increases and electronegativity decreases. This results in the decrease in M-M bond energy. Hence the catenation property decreases.
Bond energy is the amount of energy required to
Upvote